<span>Nine hundred fifty-four thousandths</span>
Answer:
at least 5
Step-by-step explanation:
<u><em>If the question was similar to the one given below </em></u>
A researcher plans to identify each participant in a certain medical experiment with a code consisting of either a single letter or a pair of distinct letters written in alphabetical order. What is the least number of letters that can be used if there are 12 participants, and each participant is to receive a different code?
<em><u>The answer would be as follows</u></em>
If we use 3 letters or any distinct letter as a comma such that 2 are in alphabetical order then we would get
4C2= 6 ways to use these letters and the comma
If we use 4 letters or any distinct letter as a comma such that 2 are in alphabetical order then we would get
5C2= 10 ways to use these letters and the comma
If we use 5 letters or any distinct letter as a comma such that 2 are in alphabetical order then we would get
6C2= 15 ways to use these letters and the comma
We need the least number of the alphabets to assign codes to 12 participants.
So the least number of alphabets is 5 because it can give codes to at least to 12 people .
Pair of alphabets + distinct letter ≥ 12
5 + 1 ≥ 12
6c2 ≥ 12
15 ≥ 12
1. I cant really see it so I'm going to skip it
2. 6
3. I think its the third column
4. I'm not sure
5. burger, milk, fruit and hotdog, apple juice, fruit
6. I can't really see it
(I hope this helps you, I'm sorry for not answering some of the question, if you need help you can ask for help)
Answer:
c
Step-by-step explanation:
