Can u guys help me plssss it’s due tmw

Mathematics

2 answers:

AveGali [126]3 years ago

7 0

I’ll help u because I know it’s probably so hard but I hope u text back

Aliun [14]3 years ago

5 0

A. convert 1 hour, 18 mins, 27 secs to hours.
1+(18÷60)+27÷3,600)=1.3075 hours

26.2 miles in 1.3075= 26.2 miles / 1.3075 hr
= 26.2÷1.3075/1.3075÷1.3075
(divide the numerator and the denominator by 1.3075)

= 20.04/1

B. divide the distance by the average speed to find the time.

30 miles
---------------
20.04 mph ( which equals 1.497 hours)

so it would take 1.5 hours

Hope this helped!

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Which point below would you use with the point (-2, -5) to get a line with a slope of -1?

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Answer:

$\displaystyle (-1, -6)$

Step-by-step explanation:

Find the <em>rate of change</em> [<em>slope</em>]:

$\displaystyle \frac{-y_1 + y_2}{-x_1 + x_2} = m \\ \\ \frac{5 - 6}{2 - 1} = -\frac{1}{1} = -1$

I am joyous to assist you anytime.

4 0

2 years ago

Read 2 more answers

5. Find the value(s) of x so that the line containing the points (2x + 3, x + 2) and (0, 2) is

Dvinal [7]

Answer:

x = -2 or -9

Step-by-step explanation:

You want the values of x such that the line defined by the two points (2x+3, x+2) and (0, 2) is perpendicular to the line defined by the two points (x+2, -3-3x) and (8, -1).

<h3>Slope</h3>

The slope of a line is given by the slope formula:

m = (y2 -y1)/(x2 -x1)

Using the formula, the slopes of the two lines are ...

m1 = (2 -(x+2))/(0 -(2x+3)) = (-x)/(-2x-3) = x/(2x +3)

and

m2 = (-1 -(-3-3x))/(8 -(x+2)) = (2+3x)/(6 -x)

<h3>Perpendicular lines</h3>

The slopes of perpendicular lines have product of -1:

$\dfrac{x}{2x+3}\cdot\dfrac{2+3x}{6-x}=-1\\\\x(3x+2)=(2x+3)(x-6)\qquad\text{multiply by $(2x+3)(6-x)$}\\\\3x^2+2x=2x^2-9x-18\qquad\text{eliminate parentheses}\\\\x^2+11x+18=0\qquad\text{put in standard form}\\\\(x+2)(x+9)=0\qquad\text{factor}$