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andreyandreev [35.5K]
3 years ago
12

Please can someone answer this for 1000 points

Mathematics
1 answer:
julia-pushkina [17]3 years ago
3 0

Answer:

can we really get 1000 points:(

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Convert the following systems of equations to an augmented matrix and use Gauss-Jordan reduction to convert to an equilivalent m
Rasek [7]

Answer:

System of equations:

x_1+2x_2+2x_3=6\\2x_1+x_2+x_3=6\\x_1+x_2+3x_3=6

Augmented matrix:

\left[\begin{array}{cccc}1&2&2&6\\2&1&1&6\\1&1&3&6\end{array}\right]

Reduced Row Echelon matrix:

\left[\begin{array}{cccc}1&2&2&6\\0&1&1&2\\0&0&1&1\end{array}\right]

Step-by-step explanation:

Convert the system into an augmented matrix:

\left[\begin{array}{cccc}1&2&2&6\\2&1&1&6\\1&1&3&6\end{array}\right]

For notation, R_n is the new nth row and r_n the unchanged one.

1. Operations:

R_2=-2r_1+r_2\\R_3=-r_1+r_3

Resulting matrix:

\left[\begin{array}{cccc}1&2&2&6\\0&-3&-3&-6\\0&-1&1&0\end{array}\right]

2. Operations:

R_2=-\frac{1}{3}r_2

Resulting matrix:

\left[\begin{array}{cccc}1&2&2&6\\0&1&1&2\\0&-1&1&0\end{array}\right]

3. Operations:

R_3=r_2+r_3

Resulting matrix:

\left[\begin{array}{cccc}1&2&2&6\\0&1&1&2\\0&0&2&2\end{array}\right]

4. Operations:

R_3=\frac{1}{2}r_3

Resulting matrix:

\left[\begin{array}{cccc}1&2&2&6\\0&1&1&2\\0&0&1&1\end{array}\right]

4 0
3 years ago
In a certain​ city, the record rainfall during an 24​-hour period is 14 and one fourth inches. How much rain fell per hour on​ a
lubasha [3.4K]

Answer:

the answer us about .53 per hour

Step-by-step explanation:

You just divide 14.25 by 24

4 0
3 years ago
A rabbit weighs 4 pounds and 6 ounces how many ounces does the rabbit weigh
docker41 [41]
There are 16 ounces in a pound. If there are 4 pounds, then you take 16 and multiply it by 4 and then add 6.

The answer is: 70.
7 0
3 years ago
Read 2 more answers
Consider the standard normal curve given.
Harman [31]

Answer:

mean: 30

standard dev: 5

the data point 37 is more than

Step-by-step explanation:

4 0
3 years ago
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The length of a rectangle is 3 less than twice the width. Write a function rule for the perimeter in terms of w, the width
Nitella [24]

l = 2w-3

P = 2(l+w)

substitute in for l

P = 2(2w-3 +w)

combine like terms

P = 2(3w-3)

P = 6w-6

P(w) = 6(w-1)


3 0
3 years ago
Read 2 more answers
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