There are two solutions.
.. (3, 2)
.. (0.2, -3.6)
_____
If you're choosing possibilities from a list, trying them in the equations usually gives quick results.
<span>1.Rename with common denominators.
2.Regroup the first fraction.
3.Subtract the whole numbers and numerators.
<span>4.Simplify (if necessary)</span></span>
Given that,
Sample size= 83
Mean number= 39.04
Standard deviation= 11.51
We know the critical t-value for 95% confidence interval which is equal to 1.989.
We also know the formula for confidence interval,
CI=( mean number - critical t-value*standard deviation/(sample size)^(1/2), mean number + critical t-value*standard deviation/(sample size)^(1/2))
So, we have
CI= (39.04 - 1.989*11.51/83^(1/2), 39.04 + 1.989*11.51/83^(1/2)
CI= (39.04 - 2.513,39.04 + 2.513)
CI= (36.527,41.553)
Therefore, 95% confidence interval for these data is (36.527,41.553), and this result interpret that the true value for this survey sample lie in the interval (36.527,41.553).
$143
add the two discounts of 25 and 10 percent. then your item will be 65% of the price now.
Answer:
A
Step-by-step explanation:
All of the others equal -8
I hope this helps
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if wrong pls leave a comment
