Answer:
ya
Step-by-step explanation:
Considering the concepts of the mean and the median of a distribution, the distribution of dates would be skewed to the left because the <u>mean would be less than the median</u>.
<h3>What are the mean and the median of a distribution?</h3>
- The mean of a data-set is given by the <u>sum of all observations divided by the number of observations</u>.
- The median of a data-set is the middle value of the data-set, the value which 50% of the measures are less and 50% are greater.
A distribution is classified as left skewed if the <u>mean is less than the median</u>.
In this problem, we have that most coins would be from the current year, hence the median should be the current year, while there are no coins from a year ahead of the current year and there should be a few coins of older years, hence the mean would assume a value less than the median and the distribution would be left skewed.
More can be learned about the mean and the median of a distribution at brainly.com/question/24732674
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At x=2, y=4
At x=4, y=16
So the total change in y from x=2 to x=4 is 16-4=12
And since average rate of change = total change in y divided by total change in x within the same period, therefore the answer is 12/2 = 6
Hope that helps. Let me know if you have any questions.
1) there were 32 bales added
2) 8 hours
3) 74 cards
4) 11 packs
5) $57
6) ummm...$3?
7) began with 12
8) $5 per candy bar
9) 44 students on each bus
10) $77 spent on baseball gear
X + 6 is greater than (>) or equal to (=) 15
