1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
algol13
3 years ago
9

Pls help (5th grade)

Mathematics
2 answers:
Juli2301 [7.4K]3 years ago
6 0

Answer: 4.523

Here is an image that might help you understand placements.

Helga [31]3 years ago
5 0

Answer:

rounded to the nearest thousandth would be 4.523

You might be interested in
Help please!!!! will upvote answers!!!!
statuscvo [17]
Formula for finding the area of a rectangle: length x width

Formula for finding the volume of a rectangular prism: V = lwh
7 0
3 years ago
Find the sum and choose the correct answer.
Alborosie
B, n to the 3rd power + 4n to the 2nd power +8n -16
5 0
3 years ago
Read 2 more answers
A tank contains 10 liters of pure water. Saline solution with a variable concentration 5 grams of salt per liter is pumped into
algol [13]

Answer:

dQ(t)/dt = 20 - 2Q(t)/5 , Q(0) = 0

Step-by-step explanation:

The mass flow rate dQ(t)/dt = mass flowing in - mass flowing out

Since 5 g/L of salt is pumped in at a rate of 4 L/min, the mass flow in is thus 5 g/L × 4 L/min = 20 g/min.

Let Q(t) be the mass present at any time, t. The concentration at any time ,t is thus Q(t)/volume = Q(t)/10. Since water drains at a rate of 4 L/min, the mass flow out is thus, Q(t)/10 g/L × 4 L/min = 2Q(t)/5 g/min.

So, dQ(t)/dt = mass flowing in - mass flowing out

dQ(t)/dt = 20 g/min - 2Q(t)/5 g/min

Since the salt just begins to be pumped in, the initial mass of salt in the tank is zero. So Q(0) = 0

So, the initial value problem is thus

dQ(t)/dt = 20 - 2Q(t)/5 , Q(0) = 0

3 0
2 years ago
Question Progress<br> Decrease £250 by 15%
balandron [24]

Answer:

215 i guess

Step-by-step explanation:

8 0
3 years ago
An unfair coin with​ Pr[H] = 0.2 is flipped. If the flip results in a​ head, a marble is selected at random from a urn containin
satela [25.4K]
Normally when dealing with coins the probability of getting heads or tails is 0.5 each. However in this case since its an unfair coin, the probability of getting heads is 0.2. 
H - head 
T - tails
R - red marble
pr (H) = 0.2
urn
6 red and 4 blue
pr (T)   = 0.8
urn
3 red and 5 blue

when heads is obtained 
red - 6/10 -0.6
blue - 4/10 - 0.4
therefore when multiplying with 0.2 probability of getting heads
pr (R ∩ H) red - 0.6*0.2 = 0.12

when tails is obtained 
red - 3/8 - 0.375
blue - 5/8 - 0.625
when multiplying with 0.8 probability of getting tails
pr (R ∩ T) red - 0.375 * 0.8 = 0.3

using bayes rule the answer can be found out, 
the following equation is used;
pr (H | R) = pr (R ∩ H) / {pr (R ∩ H) + pr (R ∩ T)}
               = 0.12 / (0.12 + 0.3)
               = 0.12 / 0.42
               = 0.286
the final answer is 0.286
6 0
3 years ago
Other questions:
  • What is the area of parallelogram RSTU?
    8·2 answers
  • What is the projection of (4,4) onto (-7,3)?
    5·1 answer
  • Bob and Cheryl are taking a road trip that is 188.3 miles. Bob drove 5/7 of the total
    5·1 answer
  • Six aides work 6-1/2 Hours at $4.00 an hour,what are the total wages
    13·1 answer
  • 27 less than twice a number is negative 1
    5·1 answer
  • How much more would the value of y be on the graph than its value
    14·1 answer
  • What is the solution to this inequality?<br><br> −4x−8&gt;−20
    10·1 answer
  • What is the value <br> 14x +18 = 118
    5·1 answer
  • The ages of two sisters are consecutive even integers. Twice the age of the youngest exceeds the oldest by 8. How old is the you
    12·2 answers
  • Please helppp asappppp
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!