<span>2. scalene, isosceles, equilateral</span>
Answer: the distance of the base of the house to the foot of the ladder is 6.84 feet
Step-by-step explanation:
The scenario is shown in the attached photo.
Right angle triangle ABC is formed when the ladder leans against the wall of the house.
AC = the height of the ladder
AB = x feet = distance of the base of the house to the foot of the ladder
BC is the wall of the building.
To determine x, we will apply trigonometric ratio
Cos # = adjacent/hypotenuse
Where
# = 70 degrees
Hypotenuse = 20
Adjacent = x
Cos 70 = x/20
x = 20cos70
x = 20 × 0.3420
x = 6.84 feets
X = 5 (you can set it up as a regular equation)
9x + 1= 46
9x = 45 (subtracted 1 from both sides)
x = 5 (divided 45 by 9)
hope this helps :)
Look at the graph below carefully
Observe the results of shifting ={2}^{x}f(x)=2x
vertically:
The domain, (−∞,∞) remains unchanged.
When the function is shifted up 3 units to ={2}^{x}+3g(x)=2x +3:
The y-intercept shifts up 3 units to (0,4).
The asymptote shifts up 3 units to y=3y=3.
The range becomes (3,∞).
When the function is shifted down 3 units to ={2}^{x}-3h(x)=2 x −3:
The y-intercept shifts down 3 units to (0,−2).
The asymptote also shifts down 3 units to y=-3y=−3.
The range becomes (−3,∞).