Symmetrical functions can be about the x and y axis. Essentially, if we reflect the graph across the y or x axis, we get the same graph. Some other graphs can be reflected across both the x and y axis at the same time and be symmetrical. These can be classified as odd and even functions. You can test this by replacing x and y with -x and -y and simplify the equation. If the results comes out to be the same as the original, it is symmetrical across the origin.
Best of Luck!
Answer:
I got x=5/2; y=0 lmk if it works
Step-by-step explanation:
First one:
cos(A)=AC/AB=3/4.24
cos(B)=BC/AB=3/4.24
Cos(A)/cos(B)=AC/AB / (BC/AB) = AC/AB * AB/BC = AC/BC=3/3=1
Second one:
To solve this problem, we have to ASSUME AFE is a straight line, i.e. angle EFB is 90 degrees. (this is not explicitly given).
If that's the case, AE is a transversal of parallel lines AB and DE.
And Angle A is congruent to angle E (alternate interior angles).
Therefore sin(A)=sin(E)=0.5
Answer:
The answer would be the third option, segment AS
Answer:
do 49 x 49 which equals 2,401 then check it
put 2,401 square root which equals 49
