The space between the two spheres will be the volume of the larger sphere minus the volume of the smaller sphere. Given that the volume of any sphere is:
V=(4πr^3)/3 The space between to sphere of different radius and positioned about the same center is:
S=(4πR^3)/3-(4πr^3)/3 I used S=volume of space, R=larger radius and r=smaller radius...
S=(4π/3)(R^3-r^3), we are told that R=5 and r=4 so
S=(4π/3)(5^3-4^3)
S=(4π/3)(125-64)
S=(4π/3)(61)
S=244π/61
S=4π cm^3
S≈12.57 cm^3 (to nearest hundredth of a ml)
A is the answer i have to write 20 characters so I am writing random things
Given two points (x₁,y₁) and (x₂,y₂)the slope passes through these points will be:
m=(y₂-y₁)/(x₂-x₁)
In this case the slope will be:
(7,-8)
(-4,6)
m=(6+8)/(-4-7)=14/-11=-14/11
point-slope form of a line: we need a point (x₀,y₀) and the slope (m).
y-y₀=m(x-x₀)
In this case, we know the slope (m=-14/11), and we can choose either of two points. The line will be the same.
(-4,6)
m=-14/11
y-y₀=m(x-x₀)
y-6=-14/11(x+4) ⇒ (point-slope form)
<span>Answer: D. y-6=-14/11(x+4)</span>
