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mamaluj [8]
3 years ago
12

Define the sequence recursively using function notation. 2.5, 7.5, 22.5, 67.5, 202.5,...

Mathematics
1 answer:
Lubov Fominskaja [6]3 years ago
5 0

Answer: Aₙ = Aₙ₋₁*3;  where A₀ = 2.5

Step-by-step explanation:

Let's try with some known sequences:

Arithmetic.

The difference between consecutive terms is constant:

7.5 - 2.5 = 5

22.5 - 7.5 = 15

We can already see that it is not an arithmetic sequence.

Geometric:

The ratio between consecutive terms is constant.

7.5/2.5 = 3

22.5/7.5 = 3

67.5/22.5 = 3

...

We can already see that this is a geometric sequence.

Then we can write the n-th term as:

Aₙ = Aₙ₋₁*3, where A₀ = 2.5

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Find the least common denominator for these<br> two rational expressions.<br> 8/n<br> n/7n²
Serga [27]

Answer:

7n^2

Step-by-step explanation:

Multiply 8/n by 7n/7n to get 56n/7n^2

5 0
2 years ago
In ΔABC, m∠B = m∠C. The angle bisector of ∠B meets AC at point H and the angle bisector of ∠C meets AB at point K. Prove that BH
solniwko [45]

Answer:

See explanation

Step-by-step explanation:

In ΔABC, m∠B = m∠C.

BH is angle B bisector, then by definition of angle bisector

∠CBH ≅ ∠HBK

m∠CBH = m∠HBK = 1/2m∠B

CK is angle C bisector, then by definition of angle bisector

∠BCK ≅ ∠KCH

m∠BCK = m∠KCH = 1/2m∠C

Since m∠B = m∠C, then

m∠CBH = m∠HBK = 1/2m∠B = 1/2m∠C = m∠BCK = m∠KCH   (*)

Consider triangles CBH and BCK. In these triangles,

  • ∠CBH ≅ ∠BCK (from equality (*));
  • ∠HCB ≅ ∠KBC, because m∠B = m∠C;
  • BC ≅CB by reflexive property.

So, triangles CBH and BCK are congruent by ASA postulate.

Congruent triangles have congruent corresponding sides, hence

BH ≅ CK.

5 0
3 years ago
For a function p(x)= x^2-9, what is the inverse function for the domain [0, infinity\
kkurt [141]
An inverse function is a function that reverses another function, so we have a function called:

p(x)

Then, the inverse function will be as follows:

p^{-1}(x)

Given that y = p(x), we need to isolate x in terms of y:

y =  x^{2} -9
∴ y+9 = x^{2}

So:

x=+\sqrt{y+9} and x=-\sqrt{y+9}

therefore, exchanging variables x and y:

y=+\sqrt{x+9} and y=-\sqrt{x+9}
p^{-1}(x)=+\sqrt{x+9} and p^{-1}(x)=-\sqrt{x+9}

Which are the figures shown below.

7 0
4 years ago
Suppose you can factor x^2 + bx + c as (x + p)(x + q). If c &gt; 0, what could be possible values of p and q?
ad-work [718]

p could be 5 and q could be 8 this is just my guess but i think its right

3 0
3 years ago
Wilma and Fred rode their bikes toward each other from points on a straight road 32 miles apart. If Fred rode 3 miles per hour f
Firdavs [7]

Answer:

wilma is 22.5 mph

fred is 25.5 mph

Step-by-step explanation:

Time:40 minutes, or 2/3 hours

Speed:

Fred:x+3

Wilma: x

Distance:32 miles

2/3(x+x+3)=32

2/3(2x+3)=32

1 1/3x+2=32

4/3x=30

x=22.5

wilma is 22.5 mph

fred is 22.5+3= 25.5 mph

6 0
3 years ago
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