Log(66)
log(6 × 11)
log(6) + log(11)
A= 4 B= 2 C= -1
follow the formula ax^2 + bx + c= 0.
Ok sure! Let's start with the marbles first. We have one red one blue and one green. There is a red and a blue cube. All we do is list the possible combinations of one marble and one cube. The answer would be : 1 blue marble, 1 blue cube. 1 red marble, 1 blue cube. 1 green marble, 1 blue cube. Then again but with the red cube. So in all, there are 6 possible combinations. Hope this helps. ☺️
Its asking how much did they both spent, in total, in order to reach the same amount spent in part A
