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LenKa [72]
3 years ago
9

What exponential function is the best fit for the data in the table? x f(x) 3 10 4 16 5 28

Mathematics
2 answers:
Svetradugi [14.3K]3 years ago
6 0

Answer:

f(x) = 3(2)^x − 2  + 4

*(Also seen as choice A on the quiz, took it moments ago and got it correct, best of luck!)


Gre4nikov [31]3 years ago
3 0
Use excel to draw the graph and add the trend, formula

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Which relation is also a function?
ratelena [41]

Answer:

{ (0, 0), (4, 0), (6, 0) }

Step-by-step explanation:

In order to be a function, ordered pairs must have values of x, or the domain, that are different and do not repeat.

4 0
3 years ago
What is the value of f (x) = 1/2 x + 5 when x=4
Anna35 [415]
Replace all values of x as 4

f(4)=1/2(4)+5
f(4)=4/2+5
f(4)=2+5
f(4)=7

Hope I helped :)
7 0
3 years ago
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Health insurers are beginning to offer telemedicine services online that replace the common office visit. A company provides a v
Veronika [31]

Answer:

\text {CI} = (60.54, \: 81.46)\\\\

Therefore, we are 95% confident that actual mean savings for a televisit to the doctor is within the interval of ($60.54 to $81.46)

Step-by-step explanation:

Let us find out the mean savings for a televisit to the doctor from the given data.

Using Excel,

=AVERAGE(number1, number2,....)

The mean is found to be

\bar{x} = \$71  

Let us find out the standard deviation of savings for a televisit to the doctor from the given data.

Using Excel,

=STDEV(number1, number2,....)

The standard deviation is found to be

 s = \$ 22.35

The confidence interval is given by

\text {confidence interval} = \bar{x} \pm MoE\\\\

Where the margin of error is given by

$ MoE = t_{\alpha/2}(\frac{s}{\sqrt{n} } ) $ \\\\

Where n is the sample of 20 online doctor visits, s is the sample standard deviation and t_{\alpha/2} is the t-score corresponding to a 95% confidence level.

The t-score is given by is

Significance level = α = 1 - 0.95 = 0.05/2 = 0.025

Degree of freedom = n - 1 = 20 - 1 = 19

From the t-table at α = 0.025 and DoF = 19

t-score = 2.093

So, the margin of error is

MoE = t_{\alpha/2}(\frac{s}{\sqrt{n} } ) \\\\MoE = 2.093\cdot \frac{22.35}{\sqrt{20} } \\\\MoE = 2.093\cdot 4.997\\\\MoE = 10.46\\\\

So the required 95% confidence interval is

\text {CI} = \bar{x} \pm MoE\\\\\text {CI} = 71 \pm 10.46\\\\\text {CI} = 71 - 10.46, \: 71 + 10.46\\\\\text {CI} = (60.54, \: 81.46)\\\\

Therefore, we are 95% confident that actual mean savings for a televisit to the doctor is within the interval of ($60.54 to $81.46)

7 0
3 years ago
The graph represents the height y, in meters, above the ground of a water balloon x seconds after it is dropped from a window.
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Answer:

you cant do that

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