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Lapatulllka [165]
2 years ago
15

Triangle TRS is similar to triangle TMN. Angle T = 40°, angle R = 60°, and angle S = 80° . What is the measure of angle M

Mathematics
1 answer:
Andre45 [30]2 years ago
7 0

Answer:

60degrees

Step-by-step explanation:

For similar triangles, the angles of their angles are equal to matter the size.

Hence if triangle TRS is similar to triangle TMN, then;

<R = <M and <S = <N

Given that;

<T = 40 degrees

<R = 60degrees

<S = 80 degrees

Since <R = <M, then <M = 60degrees

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When a distribution is mound-shaped symmetrical, what is the general relationship among the values of the mean, median, and mode
yuradex [85]

Answer:

The mean, median, and mode are approximately equal.

Step-by-step explanation:

The mean, median, and mode are <em>central tendency measures</em> in a distribution. That is, they are measures that correspond to a value that represents, roughly speaking, "the center" of the data distribution.

In the case of a <em>normal distribution</em>, these measures are located at the same point (i.e., mean = median = mode) and the values for this type of distribution are symmetrically distributed above and below the mean (mean = median = mode).

When a <em>distribution is not symmetrical</em>, we say it is <em>skewed</em>. The skewness is a measure of the <em>asymmetry</em> of the distribution. In this case, <em>the mean, median and mode are not the same</em>, and we have different possibilities as the mentioned in the question: the mean is less than the median and the mode (<em>negative skew</em>), or greater than them (<em>positive skew</em>), or approximately equal than the median but much greater than the mode (a variation of a <em>positive skew</em> case).  

In the case of the normal distribution, the skewness is 0 (zero).

Therefore, in the case of a <em>mound-shaped symmetrical distribution</em>, it resembles the <em>normal distribution</em> and, as a result, it has similar characteristics for the mean, the median, and the mode, that is, <em>they are all approximately equal</em>. So, <em>the </em><em>general</em><em> relationship among the values for these central tendency measures is that they are all approximately equal for mound-shaped symmetrical distributions, </em>considering they have similar characteristics of the <em>normal distribution</em>, which is also a mound-shaped symmetrical distribution (as well as the t-student distribution).

5 0
3 years ago
The formula for the volume of a pyramid is V = Bh. Express h in terms of B and V.<br> 0<br> 0<br> =
strojnjashka [21]

Answer:

h = \frac{V}{B}

Step-by-step explanation:

Given

V = Bh ( isolate h by dividing both sides by B )

\frac{V}{B} = h

4 0
3 years ago
Read 2 more answers
HELP PLZ WILL GIVE BRAINLIEST! find the arrithmetic means in the given sequence<br> -3,?,?,?,93
pav-90 [236]

Answer:

Step-by-step explanation:

The standard form of an arithmetic sequence is

aₙ = a₁ + d(n - 1)

where aₙ is the number of the term in the sequence (in order from first term where n = 1, to second term where n = 2, to third term where n = 3, etc) a₁ is the the first term in the sequence, and d is the arithmetic difference or means.  This is what we are looking to solve for.  

In our sequence we have the first term, -3 (where n = 1) and the fifth term, 93 (where n = 5).  If we fill in what we have, the only unknown is d, our arithmetic difference (means) between each number in the sequence.

Because we have the fifth term, we can write our standard form to fit our needs:

a₅ = a₁ + d(n-1).  Therefore,

93 = -3 + d(5 - 1) and

93 = -3 + d(4) so

96 = 4d and

d = 24

Our arithmetic difference (means) is 24.  Let's test it on a few values of n.  Let's look for the second, third, and 4th terms, and then try it out for n = 5 to make sure the 5th term, using our arithmetic sequence with d = 24 works and we do, in fact, find the fifth term to be 93.

Testing n = 2

a₂ = -3 + 24(2 - 1) so

a₂ = -3 + 24(1)  and

a₂ = 21.  Second term is 21 (Notice that difference between -3 and 21 is 24)

Testing n = 3

a₃ = -3 + 24(3 - 1) so

a₃ = -3 + 24(2) and

a₃ = 48 - 3 and

a₃ = 45 (Notice the difference between 21 and 45 is 24)

Testing n = 4

a₄ = -3 + 24(4 - 1) so

a₄ = -3 + 24(3) and

a₄ = 72 - 3 and

a₄ = 69 (Notice the difference between 45 and 69 is 24)

Testing n = 5 (and it better come out as 93 or we did something wrong!)

a₅ = -3 + 24(5 - 1) and

a₅ = -3 + 24(4) so

a₅ = 96 - 3 so

a₅ = 93 (Phew!)  ; )

5 0
3 years ago
Read 2 more answers
13 candy bars weigh 26 ounces. what is the weight of 35 candy bars?
anygoal [31]
26 oz/13 bars = 2 oz/1 bar

Each bar weighs 2 oz

multiply the amount of bars to the amount they weigh:

35 x 2 = 70

35 bars weigh 70 oz

hope this helps
6 0
3 years ago
Find an equation in standard form for the hyperbola with vertices at (0, ±3) and foci at (0, ±7)
Nitella [24]

The equation of a hyperbola is:

(x – h)^2 / a^2 - (y – k)^2 / b^2 = 1

 

So what we have to do is to look for the values of the variables:

<span>For the given hyperbola : center (h, k) = (0, 0)
a = 3(distance from center to vertices)
a^2 = 9</span>

<span>
c = 7 (distance from center to vertices; given from the foci)
c^2 = 49</span>

 

<span>By the hypotenuse formula:
c^2 = a^2 + b^2
b^2 = c^2 - a^2 </span>

<span>b^2 =  49 – 9</span>

<span>b^2  = 40

</span>

Therefore the equation of the hyperbola is:

<span>(x^2 / 9) – (y^2 / 40) = 1</span>

5 0
3 years ago
Read 2 more answers
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