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3 years ago

8

DESPERATELY NEED HELP!! TANGENT LINES; WHAT IS THE VALUE OF X? PLEASE EXPLAIN! BRAINLIEST GIVEN!!

1 answer:

ycow [4]3 years ago

4 0

I believe x is 30 degrees.

The equilateral triangle has each angle equal to 60 degrees. So the small arc near x is also 60. The angle x is half the arc so would be 30.
This also makes sense because the triangle it forms with angle x and the center has center angle of 60 and angle formed by tangent and radius of 90. So it is a 30-60-90 triangle, making angle x 30.

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1. Find the measure of arc ABC<br><br> WILL GOVE BRAINLESTT

goblinko [34]

Answer:

180? I don't know it is correct

7 0

2 years ago

The perimeter of a rectangle is 36 menters. The length of the rectangle is 4 meters longer than the width. Find the length and t

cupoosta [38]

Answer:

11 m and 7 m

Step-by-step explanation:

Width = x

Length = x+4

P=2L+2W

P=2(x+4) + 2x=4x +8

36 = 4x + 8

4x = 28

x=7 Width

x+4=7+4=11 Length

7 0

3 years ago

Solve the equation 20.5 = x + 4

devlian [24]

Answer:

16.5

Step-by-step explanation:

20.5 = x + 4

16.5 = x

x = 16.5

4 0

3 years ago

Read 2 more answers

How is this worked out ? im confused.

Rudik [331]

Answer:

From the given ratio for $tan\theta=\frac{4}{5}$ we found the values are

$sin\theta=4$

$cos\theta=5$

$csc\theta=\frac{1}{4}$

$sec\theta=\frac{1}{5}$

$cot\theta=\frac{5}{4}}$

Step-by-step explanation:

Given the ratio for $tan\theta=\frac{4}{5}$

We have to find the rest of trignometric functions:

$tan\theta=\frac{4}{5}\hfill (1)$

$tan\theta$ can be written as

$tan\theta=\frac{sin\theta}{cos\theta}\hfill (2)$

Comparing equations (1) and (2) we get

$tan\theta=\frac{sin\theta}{cos\theta}=\frac{4}{5}$

$\frac{sin\theta}{cos\theta}=\frac{4}{5}$

Equating the coressponding numerator and denominator respectively

Therefore $sin\theta=4$ and $cos\theta=5$

We can find $csc\theta$

$csc\theta=\frac{1}{sin\theta}$

$=\frac{1}{4}$ (since $sin\theta=4$ )

$csc\theta=\frac{1}{4}$

We can find $sec\theta$

$sec\theta=\frac{1}{cos\theta}$

$=\frac{1}{5}$ (since $cos\theta=5$ )

$sec\theta=\frac{1}{5}$

To find $cot\theta$ :

$cot\theta=\frac{1}{tan\theta}$

$=\frac{1}{\frac{4}{5}}$

$=1\times \frac{5}{4}$

$=\frac{5}{4}}$

$cot\theta=\frac{5}{4}}$

7 0

3 years ago

8o + 12p = 382<br> 12o + 8p = 388<br><br> What does p equal?

shutvik [7]

For this case we have a system of two equations with two variables:

Clear "o" from the first equation:

$8o = 382-12p\\o = \frac {382-12p} {8} = \frac {191-6p} {4}$

We substitute in the second equation:

$12 (\frac {191-6p} {4}) + 8p = 388\\3 (191-6p) + 8p = 388\\573-18p + 8p = 388\\-10p = 388-573\\-10p = -185\\p = \frac {185} {10}\\p = 18.5$

ANswer:

$p = 18.5$

8 0

3 years ago

Read 2 more answers