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user100 [1]
3 years ago
12

Least to greatest 6 3/10,1 3/10, 1 3/11, -7 6/14, 5 3/10

Mathematics
1 answer:
Drupady [299]3 years ago
3 0

Answer:

-7 6/14, 1 3/11, 1 3/10, 5 3/10, 6 3/10

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A newborn baby weighed 133 ounces.
Harman [31]

Answer:

precisely 8 pounds and 3125 ounces

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
What is the answer for (a^2+12c)÷7b-1
vodomira [7]

Answer:

Step-by-step explanation:

Integer roots:

a = 6 n + 1, b = 7, c = -3 n^2 - n, n element Z

a = 6 n + 5, b = 7, c = -3 n^2 - 5 n - 2, n element Z

Derivative:

d/da(1/7 (a^2 + 12 c) b - 1) = (2 a b)/7

Indefinite integral:

integral(-1 + 1/7 b (a^2 + 12 c)) da = (a^3 b)/21 + (12 a b c)/7 - a + constant

Related Queries:

5 0
3 years ago
What is the value of x?<br><br><br><br> Enter your answer in the box.<br><br> x =
galina1969 [7]
The answer is:  " 11 " .
____________________________________________________
            →     " x  =  11  "  .
____________________________________________________
Explanation:
____________________________________________________
Set up the ratio/ proportion as a fraction:

6 cm / 48 cm = 5 cm / (3x + 7) ; 

→ The "cm" units cancel out; since:  "cm/cm = 1 " ; 

→ The "6/48" = "(6 ÷ 6) / (48 ÷ 6) =  " 1/8 " ; 

→ Rewrite as:  \frac{1}{8} = \frac{5}{3x + 7} ;

Now, we can "cross-multiply" :
__________________________________________________

<u>Note</u>:  Given: \frac{a}{b} = \frac{c}{d} ;  ad = bc ; 
              {b\neq 0 ;  d \neq 0} .
__________________________________________________
 
As such:      
 
    1 * (3x + 7) = 8 * 5 ;

   →  3x + 7 = 40 ; 

Subtract "7" from each side of the equation:

   →  3x + 7 − 7 = 40 <span>− 7 ; 
</span>
to get:  

   → 3x = 33 ; 

Now, divide each side of the equation by "3" ; 
   to isolate "x" on one side of the equation; & to solve for "x" ; 

   →  3x / 3 = 33 / 3 ; 

to get: 
____________________________________________________
  
   →    " x = 11 " .
____________________________________________________
   →   The answer is:  " 11 " .
____________________________________________________
4 0
3 years ago
Read 2 more answers
What is the equation of the circle with center (5,-4) and containing the points (5,-2)
gtnhenbr [62]

Answer:

The equation of a circle is (x-5)^2+(y+4)^2=4 .

Step-by-step explanation:

-The equation of a circle is:

(x-h)^2+(y-k)^2=r^2 (where center is (h,k), the point (x_{1},y_{1}) and the radius known as r).

-Use the center (5,-4) and the point (5,-2) for the equation:

(5-5)^2+(-2+4)^2=r^2

-Solve the equation:

(5-5)^2+(-2+4)^2=r^2

0 + (-2)^2=r^2

4 = r^2

\sqrt{4} = \sqrt{r^2}

2 = r

-After you found the radius, use the center (5, -4)  and radius 2 to get the equation of a circle:

(x-5)^2+(y+4)^2=2^2

-Then, after you have the equation, the radius needs to simplified by the exponent:

(x-5)^2+(y+4)^2=4

3 0
3 years ago
In ΔNOP, \overline{NP} NP is extended through point P to point Q, \text{m}\angle PNO = (x+14)^{\circ}m∠PNO=(x+14) ∘ , \text{m}\a
adelina 88 [10]

Answer:

<OPQ = 23 degrees

Step-by-step explanation:

Given

Interior angles m∠PNO=(x+14) and m∠NOP=(x−1)

Exterior angle = m<OPQ = (5x-2)

The sum of interior angles is equal to the exterior angle, that is;

m∠PNO+m∠NOP = m<OPQ

x+14 + x-1 = 5x-2

2x + 13 = 5x-2

Collect like terms;

2x-5x = -2-13

-3x = -15

x = 15/3

x = 5

Get <OPQ

<OPQ = 5x - 2

<OPQ = 5(5)- 2

<OPQ = 25-2

<OPQ = 23 degrees

4 0
3 years ago
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