Answer:
The largest total area that can be enclosed will be a square of length 272 yards.
Step-by-step explanation:
First we get the perimeter of the large rectangular enclosure.
Perimeter of a rectangle =2(l + w)
Perimeter of the large rectangular enclosure= 1088 yard
Therefore:
2(L+W)=1088
The region inside the fence is the area
Area: A = LW
We need to solve the perimeter formula for either the length or width.
2L+ 2W= 1088 yd
2W= 1088– 2L
W = 
W = 544–L
Now substitute W = 544–L into the area formula
A = LW
A = L(544 – L)
A = 544L–L²
Since A is a quadratic expression, we re-write the expression with the exponents in descending order.
A = –L²+544L
Next, we look for the value of the x coordinate


L=272 yards
Plugging L=272 yards into the calculation for area:
A = –L²+544L
A(272)=-272²+544(272)
=73984 square yards
Thus the largest area that could be encompassed would be a square where each side has a length of 272 yards and a width of:
W = 544 – L
= 544 – 272
= 272 yards
Answer:
line a and b are parallel
line c is not perpendicular because it is not 3
step-by-step explanation:
if the slope is the same it is parallel
if the slope is the complete opposite it is perpendicular
lines a and b are parallel with a slope of -1/3
(0, 5) (3, 4)
m = 4 - 5 / 3 - 0
m = -1 / 3
m = -1/3
(-1, 1) (2, 0)
m = 0 - 1 / 2 + 1
m = -1 / 3
m = -1/3
line c is perpendicular to lines a and b the slope is
(0, 0) (2, 5)
m = 5 - 0 / 2 - 0
m = 5/2
2.5
Answer:
3/2 pages per hour
Step-by-step explanation:
1 : 2/3
= 3/2 : 1
Answer:
I think it is a) exponential