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GuDViN [60]
3 years ago
11

Which of the equations are true identities? \begin{aligned} \text{A. }&(y+6)(y-7)+42=y^2-y \\\\ \text{B. }&(x+3)(x-8)=x^

2-5x \end{aligned} A. B. ​ (y+6)(y−7)+42=y 2 −y (x+3)(x−8)=x 2 −5x ​
Mathematics
2 answers:
BaLLatris [955]3 years ago
8 0

Answer:

its only A

Step-by-step explanation:

got it from khan academy

musickatia [10]3 years ago
5 0

Answer:

Only A, the first equation is true.

Step-by-step explanation:

A. (y + 6)(y – 7) + 42 = y² + 6y –7y – 42 + 42 = y² – y. This means A is true

B. (x + 3)(X – 8) = x² + 3x – 8x – 24 = x² – 5x – 24. This means B is false.

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Answer:

V=1,373.44\ cm^3

Step-by-step explanation:

<u><em>The correct question is</em></u>

A cylinder has a base with a diameter of 10.8 centimeters and height 15 centimeters. Enter the volume of the cylinder, in cubic centimeters. Round your answer to the nearest hundredth

we know that

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r=10.8/2=5.4\ cm ----> the radius is half the diameter

h=15\ cm

assume

\pi =3.14

substitute

V=(3.14)(5.4)^{2} (15)=1,373.44\ cm^3

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