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GuDViN [60]
3 years ago
11

Which of the equations are true identities? \begin{aligned} \text{A. }&(y+6)(y-7)+42=y^2-y \\\\ \text{B. }&(x+3)(x-8)=x^

2-5x \end{aligned} A. B. ​ (y+6)(y−7)+42=y 2 −y (x+3)(x−8)=x 2 −5x ​
Mathematics
2 answers:
BaLLatris [955]3 years ago
8 0

Answer:

its only A

Step-by-step explanation:

got it from khan academy

musickatia [10]3 years ago
5 0

Answer:

Only A, the first equation is true.

Step-by-step explanation:

A. (y + 6)(y – 7) + 42 = y² + 6y –7y – 42 + 42 = y² – y. This means A is true

B. (x + 3)(X – 8) = x² + 3x – 8x – 24 = x² – 5x – 24. This means B is false.

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Delvig [45]

Answer:

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3 0
2 years ago
Find the value of y so<br> that (-2,y) satisfies y =-7x?
Anit [1.1K]

Answer:

y=14

Step-by-step explanation:

plug in -2 in the place of x

y=-7(-2)    y=14

6 0
3 years ago
Can someone help me find the value of x?
musickatia [10]
47.60514678





What I did was 28 squared plus b squared equals 38.25 squared and ya......
6 0
2 years ago
00:00
masya89 [10]

Answer:

Part A = the middle one

Part B = 4 days

Step-by-step explanation:

1,300 / 4 = 325

325 x 4 = 1,300

8 0
3 years ago
Read 2 more answers
How do you write 16 tens
Rzqust [24]
16 tens = 16 x 10 = 160 ones
4 0
2 years ago
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