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3 years ago

Use remainder theorem to find f(4) f(x) = 2x^4-5x^3-8x^2-13x-6

Mathematics

1 answer:

Elan Coil [88]3 years ago

3 0

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142 equals 176 minus f

vaieri [72.5K]

Answer:

can you be more clear?

Step-by-step explanation:

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3 years ago

Read 2 more answers

Please explain how to graph this and how you did it

inysia [295]

So you would start at the origin which is 0 then go down one cause of the -1 and right 2 because of the positive 2

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3 years ago

A group of 2 adults and 4 children pay $95 for admission to a water park. A

il63 [147K]

Answer:

2a + 4c = 95

3a +7c =155

Step-by-step explanation:

2a + 4c = 95

3a +7c =155

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3 years ago

Liliana use for dark power crystals to raise 14 zombie soldiers she wants to know how many zombie soldiers Z she can race with 1

laiz [17]

Answer:

140 zombies

Step-by-step explanation:

Since this is a proportions problem and we are given three values and a variable we must solve for which is the number of zombie soldiers she can raise (z) with 10 dark power crystals. Therefore, we can use the rule of three to solve for this, in which we multiply the diagonal values and divide by the last remaining value in order to solve for the variable like so...

1 crystal <===> 14 zombies

10 crystals <===> Z zombies

(10 * 14) / 1 = 140 zombies

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2 years ago

A projectile is fired with muzzle speed 250 m/s and an angle of elevation 45° from a position 30 m above ground level. Where doe

qaws [65]

The projectile's horizontal and vertical positions at time $t$ are given by

$x=\left(250\dfrac{\rm m}{\rm s}\right)\cos45^\circ\,t$

$y=30\,\mathrm m+\left(250\dfrac{\rm m}{\rm s}\right)\sin45^\circ\,t-\dfrac g2t^2$

where $g=9.8\dfrac{\rm m}{\mathrm s^2}$ . Solve $y=0$ for the time $t$ it takes for the projectile to reach the ground:

$30+\dfrac{250}{\sqrt2}t-4.9t^2=0\implies t\approx36.2458\,\mathrm s$

In this time, the projectile will have traveled horizontally a distance of

$x=\dfrac{250\frac{\rm m}{\rm s}}{\sqrt2}(36.2458\,\mathrm s)\approx6400\,\mathrm m$

The projectile's horizontal and vertical velocities are given by

$v_x=\left(250\dfrac{\rm m}{\rm s}\right)\cos45^\circ$

$v_y=\left(250\dfrac{\rm m}{\rm s}\right)\sin45^\circ-gt$

At the time the projectile hits the ground, its velocity vector has horizontal component approx. 176.77 m/s and vertical component approx. -178.43 m/s, which corresponds to a speed of about $\sqrt{176.77^2+(-178.43)^2}\dfrac{\rm m}{\rm s}\approx250\dfrac{\rm m}{\rm s}$ .

7 0

3 years ago