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frez [133]
3 years ago
6

Select the correct answer. A truck moves 60 kilometers east from point A to point B. At point B, it turns back west and stops 15

kilometers away from point A. What are the total distance and total displacement of the truck? A. The total distance is 105 kilometers, and the total displacement is 15 kilometers east. B. The total distance is 105 kilometers, and the total displacement is 45 kilometers east. C. The total distance is 60 kilometers, and the total displacement is 60 kilometers east. D. The total distance is 60 kilometers, and the total displacement is 45 kilometers east. E. The total distance is 105 kilometers, and the total displacement is 75 kilometers east.
Physics
1 answer:
katovenus [111]3 years ago
8 0

Answer:

Option a

Explanation:

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How is a family defined
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Two point charges are separated by 10 cm, with an attractive force between them of 15 N. Find the force between them when they a
suter [353]

Answer:

(a) the force is 8.876 N

(b) the magnitude of each charge is 4.085 μC

Explanation:

Part (a)

Given;

coulomb's constant, K = 8.99 x 10⁹ N.m²/C²

distance between two charges, r = 10 cm = 0.1 m

force between the two charges, F = 15 N

when the distance between the charges changes to 13 cm (0.13 m)

force between the two charges, F = ?

Apply Coulomb's law;

F = \frac{Kq_1q_2}{r^2} \\\\let \ Kq_1q_2 = C\\\\F =\frac{C}{r^2} \\\\C = Fr^2\\\\F_1r_1^2 = F_2r_2^2\\\\F_2 =\frac{F_1r_1^2}{r_2^2} \\\\F_2 = \frac{15*0.1^2}{0.13^2} \\\\F_2 = 8.876 \ N

Part (b)

the magnitude of each charge, if they have equal magnitude

F = \frac{KQ^2}{r^2}

where;

F is the force between the charges

K is Coulomb's constant

Q is the charge

r is the distance between the charges

F = \frac{KQ^2}{r^2} \\\\Q = \sqrt{\frac{Fr^2}{K} } \\\\Q =  \sqrt{\frac{15*(0.1)^2}{8.99*10^9} } = 4.085 *10^{-6} \ C\\\\Q = 4.085 \ \mu C

4 0
3 years ago
What is the kinetic energy in joules of a 0.05. kg bullet traveling 310 m/s
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The formula is=1/2(m x v^2)

so = 1/2*(0.05)*(310)^2

ans is =2402.5 joules
3 0
3 years ago
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