A thought experiment aims to promote speculative thinking, logical reasoning, and paradigm shifts. Thought experiments force us to address problems we find difficult to answer, which forces us out of our comfort zone. They highlight knowledge gaps and aid in recognizing the boundaries of what is knowable.
<h3>What are thought experiments?</h3>
Thought experiments are imaginative methods for examining the nature of things. They are employed for a variety of purposes in a number of disciplines, including physics, economics, history, mathematics, and philosophy.
A thought experiment is a test that we do in our minds. Here, we will imagine a specific scenario, consider some of its repercussions, and come to a broad conclusion.
Therefore, a thought experiment aims to promote speculative thinking, logical reasoning, and paradigm shifts. Thought experiments force us to address problems we find difficult to answer, which forces us out of our comfort zone. They highlight knowledge gaps and aid in recognizing the boundaries of what is knowable.
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Answer:
efficiancy=40 percent
Explanation:
efficiency=energy output/energy input×100
efficiancy=8J/20J×100
efficiancy=0.4×100
efficiancy=40 percent
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Answer:
y = 428.67 m and x all = 1513.68 m
Explanation:
This problem of kinematics can be divided into two parts: a first part when the rockets work a second as a parabolic launch.
Let's do the first part, let's calculate the speed just when the engines turn off
vf = v₀ + at
vf = 78 + at
vf = 78 +12 3
vf = 114 m / s
This is the speed with which the second part begins vo = 114 m / s with an Angle of 38º
Also at this time a distance is displaced, we calculate the distance traveled (in the direction of the acceleration)
d = v₀ t + ½ a t²
d = 78 3 + ½ 12 3²
d = 288 m
Let's use trigonometry to find the components
x₀ = d cos 38 = 288 cos 38
y₀ = d sin38 = 288 sin38
x₀ = 226.95 m
y₀ = 177.31 m
Second part
Let's calculate the maximum height, at this point its vertical speed is zero (vfy = 0)
Let's decompose the initial velocity using trigonometry
vₓ = v₀ cos 38
= v₀ sin38
vₓ = 114 cos 38
= 114 sin38
vₓ = 89.83 m / s
= 70.19 m / s
² = ² - 2g (y -y₀)
0 = ² -2g (y -yo)
y-y₀ = ² / 2g
y-y₀ = 70.19²/2 9.8
y = 251.36 + y₀
y = 251.36 + 177.31
y = 428.67 m
This is the maximum height from the point where the movement began, that is, the ground.
Now let's calculate the range
R = vo² sin 2θ / g
R = 114² sin 2 38 /9.8
R = 1286.73 m
This is the scope of the parabolic movement, we must add the horizontal distance traveled in the first part
x all = R + xo
x all = 1286.73 + 226.95
x all = 1513.68 m