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2 years ago

How many solutions does the following system of equations have?

Mathematics

1 answer:

musickatia [10]2 years ago

5 0

Answer:

There is one solution.

You use substitution;

2(3x+2)=5x+4

6x+4=5x+4

x+4=4

x=0

y=2

To verify your answer, pug in x and y into both equations.

Step-by-step explanation:

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For 10-18, Determine whether the triangles can be proved

navik [9.2K]

Answer:

180 - 92 - 41 = 47

There are not two similar congruent angle in the triangles.

Hope this helps!

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2 years ago

Please help! Solve for x: -4x - 3/5 = 1/3 4x + 3/5 = 1/3 Please include a step-by-step explanation. Thank you!

vodka [1.7K]

Answer:

-4(-7/30)-3/5=1/3

4(-1/15)+3/5=1/3

Step-by-step explanation:

1. -4x-3/5=1/3

-4x=1/3+3/5

-4x=14/15 <- divide both sides

x= -7/30

2. 4x+3/5=1/3

4x=1/3-3/5

4x= -4/15 <-divide both sides

x= -1/15

5 0

3 years ago

Read 2 more answers

A box of Georgia peaches has 3 bad and 12 good peaches. (a) If you make a peach cobbler of 12 peaches randomly selected from the

Eddi Din [679]

Answer:

a) 0.21% probability that there are no bad peaches in the peach cobbler.

b) 99.79% probability of having at least 1 bad peach in the peach cobbler

c) 7.91% probability of having exactly 2 bad peaches in the peach cobbler.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

The order in which the peaches are chosen is not important. So the combinations formula is used to solve this question.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

(a) If you make a peach cobbler of 12 peaches randomly selected from the box, what is the probability that there are no bad peaches in the peach cobbler?

Desired outcomes:

12 good peaches, from a set of 12. So

$D = C_{12,12} = \frac{12!}{12!(12 - 12)!} = 1$

Total outcomes:

12 peaches, from a set of 15. So

$T = C_{15,12} = \frac{15!}{12!(15 - 12)!} = 455$

Probability:

$p = \frac{D}{T} = \frac{1}{455} = 0.0021$

0.21% probability that there are no bad peaches in the peach cobbler.

(b) What is the probability of having at least 1 bad peach in the peach cobbler?

Either there are no bad peaches, or these is at least 1. The sum of the probabilities of these events is 100%. So

p + 0.21 = 100

p = 99.79

99.79% probability of having at least 1 bad peach in the peach cobbler

(c) What is the probability of having exactly 2 bad peaches in the peach cob- bler?

Desired outcomes:

2 bad peaches, from a set of 3.

One good peach, from a set of 12.

$D = C_{3,2}*C_{12,1} = \frac{3!}{2!(3-2)!}*\frac{12!}{1!(12 - 1)!} = 36$

Total outcomes:

12 peaches, from a set of 15. So

$T = C_{15,12} = \frac{15!}{12!(15 - 12)!} = 455$

Probability:

$p = \frac{D}{T} = \frac{36}{455} = 0.0791$

7.91% probability of having exactly 2 bad peaches in the peach cobbler.

3 0

2 years ago

Why is 3^7 equal to 7 1/3

valentinak56 [21]

The required answer is $(7^{\frac{1}{3}})^{3} = (7^{\frac{1}{3}*3}) = 7^1=7$ .

what is a power rule for exponents ?

$(a^m)^n=a^{mn}$ is known as the power rule for exponents. Exponent times power is how you raise a number with an exponent to a power.

A number's exponent demonstrates how many times we are multiplying a given number by itself. 3^4, for instance, indicates that we are multiplying 3 by four. 3*3*3*3 is its expanded form. The power of a number is another name for an exponent. It could be an integer, a fraction, a negative integer, or a decimal.

$(7^{\frac{1}{3}})^{3} = (7^{\frac{1}{3}*3}) = 7^1=7$

Here, we have used the rule $(a^m)^n=a^{mn}$

To learn more about the power rule for exponents from the given link

brainly.com/question/819893

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10 months ago

Write in standard form 8x2−5+7x4−9x−x5 Please explain i don't understand

FinnZ [79.3K]

-x^5+7x^4+8x^2-9x-5.....

7 0

2 years ago

Read 2 more answers