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3 years ago

7

Can zeros be written at the end of a decimal without changing the number that it represents?

2 answers:

mr_godi [17]3 years ago

7 0

Answer: yes, zeroes are simply just a place holder to make the number easier to read

Step-by-step explanation:

Gennadij [26K]3 years ago

4 0

Yes they can. Zeros can be written at the end of a decimal. They work as a place holder.
Example:
0.4 is the same as 0.40

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The selling price of a refrigerator is $584.00 if the mark up is 25% of the dealers cost what is the dealers cost?

Rzqust [24]

438 since 584 divided by .25 is 146. Then you subtract 584 and 146 to $438

6 0

4 years ago

Two curves are orthogonal if their tangent lines are perpendicular at each point of intersection. are the given families of curv

Akimi4 [234]

Hello,

$P(x,y)=x^2+y^2-ax=0\\\\
\dfrac{\partial{P}}{\partial{x}}=2x-a\\\\
\dfrac{\partial{P}}{\partial{y}}=2y\\\\


Q(x,y)=x^2+y^2-by=0\\\\
\dfrac{\partial{Q}}{\partial{x}}=2x\\\\
\dfrac{\partial{Q}}{\partial{y}}=2y-b\\\\

\dfrac{\partial{P}}{\partial{x}}*\dfrac{\partial{Q}}{\partial{x}}+\dfrac{\partial{P}}{\partial{y}}*\dfrac{\partial{Q}}{\partial{y}}=(2x-a)*2x+2y(2y-b)\\
=4x^2+4y^2-2ax-2by\\
=2(2x^2+2y^2-ax-by)\\
=2*P(x,y)+Q(x,y))\\
=2*(0+0)=0\\\\

Answer YES
$

5 0

3 years ago

The area of a ferris wheel is about 154 square meters. Which of the following is closest to the length of one of the spokes? [As

babunello [35]

Answer:

The length of one of the spoke is 7 m

Option C is correct answer.

Step-by-step explanation:

Area of Ferris Wheel = 154 square meters.

We need to find the length of one of the spokes.

We are given: Assume the spokes go from the centre to the edge of the Ferris wheel.

So, We are given area of circle and we need to find radius of circle.

The formula used is: $Area\:of\:circle=\pi \:r^2$

Putting values and finding radius

$Area\:of\:circle=\pi \:r^2\\154=3.14\:r^2\\r^2=\frac{154}{3.14}\\r^2=49\\Taking\:square\;root\\\sqrt{r^2}=\sqrt{49}\\r=7\:m$

So, Radius of circle = 7 m

The length of one of the spoke is 7 m

Option C is correct answer.

4 0

3 years ago

ABCD is a trapezium with AB= x cm, DC=( x+ 4 )cm and the distance between the parallel sides AB and DC is 1/2 x cm

horsena [70]

We know that the smaller base is x cm, the greater base is x+4 cm, and that the height is x/2 cm.

Since the area of a trapezium is given by

$A=\dfrac{(b+B)h}{2}$

If we plug the expressions we have

$A=\dfrac{(x+(x+4))\frac{x}{2}}{2}=\dfrac{(2x+4)x}{4}=\dfrac{2x^2+4x}{4}$

If this must equal 84, we can solve for x as follows: start with

$\dfrac{2x^2+4x}{4}=84$

Multiply both sides by 4:

$2x^2+4x=336$

Subtract 336 from both sides:

$2x^2+4x-336=0$

We can divide both sides by 2 to make computation simpler:

$x^2+2x-168=0$

Use the quadratic formula (or any mean you prefer) to solve this equation and get the solutions

$x_1=-14,\quad x_2=12$

We can't accept the negative solution, because it would imply

$AB=-14,\quad CD=-10$

and we can't have negative side lengths. So, the answer is 12.

4 0

3 years ago

What is 5 to the power of 20 times 4 to the power of 13

sergejj [24]

5^20= 9.5367432e+13
4^13= 67108864

4 0

3 years ago