To determine the number of possible arrangements for 6 out of 8, we should use combinations. That is
ₐC₆ = 8!/(6!2!)
Answer: b. Combination
3: 8h+24 4: 6h+21 5: 15x+45y 6: 44h+12g
7: 7jk first box 12jm second box. 8: 9ab+13a
Basically you just want to multiply the number outside the parentheses to each number inside them.
Answer:
C. (5, -3)
Step-by-step explanation:
4x + 3y = 11
x - y = 8 (multiply by 3) --> 3x - 3y = 24
4x + 3y = 11
3x - 3y = 24
---------------------add
7x = 35
x = 5
5 - y = 8
y = 5 - 8
y = -3
(5, -3)
Answer:
The graph for x-2y>=-12 needs to get y aloneso add 2y to both sides to getx >=-12 +2ythen add 12 to both sides of the in equalityx+12 >=2ynext divide each term by 2x/2 + 6 >= yy<= x/2 + 6so the graph connects (0,6) and (2,7) and shade below the solid line
