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rewona [7]
4 years ago
9

Which counting rule would you use to determine total seating arrangements for a group of 8 people at a table with 6 chairs? Sele

ct one: a. Permutation b. Combination c. Can not be determined with information given
Mathematics
1 answer:
Stolb23 [73]4 years ago
5 0
To determine the number of possible arrangements for 6 out of 8, we should use combinations. That is
ₐC₆ = 8!/(6!2!)

Answer: b. Combination
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59.67÷11.1 what's the answer show me the work
Brilliant_brown [7]

Answer:

5.375676

change the divisor 11.1 to a whole number by moving the decimal point 1 placesa to the right. then move the decimal point in the dividend the same. then you have 596.7/111=5.375

5 0
3 years ago
4(2 + 6v) You don't have to work t out if you don't want to.
shtirl [24]
8+24v you need to show your work so here

3 0
4 years ago
Which of the following terms can be combined in this expression? -3-x/5+6.2y+20.5x-3/8y
mojhsa [17]

Answer:

-\frac{x}{5} and 20.5x

-\frac{3}{8}y and 6.2y

Step-by-step explanation:

-3-x/5+6.2y+20.5x-3/8y

-3-\frac{x}{5}+6.2y+20.5x- \frac{3}{8} y

We are given an expression with 5 terms

The terms that has same variables with same exponent are like terms. WE combine only like terms. Constants are also like terms.

In the given expression , the fractions -\frac{x}{5} and 20.5x have same 'x' . so they are like terms. we can combine these terms.

the fractions -\frac{3}{8}y and 6.2y have same 'y' . so they are like terms. we can combine these terms.

8 0
3 years ago
Read 2 more answers
One measure of general health is your body mass index (BMI). Adults with a BMI between 18.5 and 24.9 are generally considered to
soldi70 [24.7K]

Answer: 0.1797

Step-by-step explanation:

Given : \mu=24.5\ \ ; \sigma=1.2

Let x be the random variable that represents BMI for adults in this country.

We assume that  BMI for adults in this country is normally distributed.

Then, z-score for x=25.6 ,\because z=\dfrac{x-\mu}{\sigma}

\Rightarrow\ z=\dfrac{25.6-24.5}{1.2}\approx0.9167

Using z-value table , we have

The probability that the person's BMI is more than 25.6 :

P(x>25.6)=P(z>0.9167)=1-P(z\leq0.9167)\\\\=1- 0.8203413=0.1796587\approx0.1797

Hence, the probability that the person's BMI is more than 25.6 = 0.1797

Hence, the probability that the person's BMI is more than 25.6 = 0.1796

Hence, the  probability of the stick's weight being 2.23 oz or greater = 0.0174

5 0
4 years ago
Who are y’all a favorite music artist?<br> Let me know what the word is.<br> Put me on!
sweet [91]

Answer:

Well I have two that i really enjoy which is Lund and Melanie Martinez

Step-by-step explanation:

Both of their music is amazing I enjoy listening to it all the time there is more i love but i would recommend this two

4 0
4 years ago
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