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3 years ago

I would appreciate the help!

Mathematics

2 answers:

barxatty [35]3 years ago

8 0

The correct answer is A

prisoha [69]3 years ago

7 0

Answer:

Step-by-step explanation:

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Find the first partial derivatives of the function. f(x, y) = x y

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$\dfrac\partial{\partial x}[xy]=y$

$\dfrac\partial{\partial y}[xy]=x$

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3 years ago

I need help with the second question in iready

jarptica [38.1K]

Answer:

The graph on the top right is the correct graph.

Step-by-step explanation:

Because the inequality is $g\leq 6$ , we know that the circle has to be closed. This leaves us with only three graphs left. We also know that it includes everything, including the decimals in between the integers, not just the integers themselves. Therefore, the graph on the top right is the correct graph.

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3 years ago

What is the diameter and radius also the area

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The diameter is 48 feet. The radius is half of the diameter, so it is 24 feet. The area can be found using the formula pi r ^ 2. So, the area is 576 pi

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3 years ago

If a > b > c > d, then which is larger, a+c or b+d ? Can we tell from a > b > c > d which of a+d and b+c is la

victus00 [196]

Answer:

1. a+c is larger than b+d

2. No way to tell whether a+d or b+c is larger.

Step-by-step explanation:

1. Which is larger, a+c or b+d?

Let a, b, c, and d be any numbers such that $a > b > c > d$ .

Specifically, note that $a > b$ , and subtracting b from both sides of the inequality, observe that $a-b > 0$ .

Similarly, $c > d$ , and subtracting d from both sides of the inequality, observe that $c-d > 0$ .

From this, add "a-b" (a positive number, as proven above) to both sides of the inequality.

$(a-b)+(c-d) > (a-b)+0$

Addition by zero (the additive identity) doesn't change anything, so the right side remains "a-b"...

$(a-b)+(c-d) > a-b$

... and "a-b" is positive...

$(a-b)+(c-d) > a-b > 0$

... so, by the transitive property of inequality...

$(a-b)+(c-d) > 0$

Recall that subtraction is addition by a negative number...
$a+(-b)+c+(-d) > 0$

...and that addition is associative and commutative, so things can be added in any order, so the middle two terms on the left side can be rearranged...

$a+c+(-b)+(-d) > 0$

Adding b + d to both sides of the inequality

$(a+c+(-b)+(-d))+(b+d) > 0+(b+d)$

... and simplifying

$a+c > b+d$

So, a+c is larger than b+d.

2. Which is larger, a+d or b+c?

Consider the following two examples:

Example 1

Suppose a=10; b=3; c=2; d=1.

Note that $a > b > c > d$ ( $10 > 3 > 2 > 1$ ) and, also observe that $a+d=(10)+(1)=11$ , and $b+c=(3)+(2)=5$ , so a+d is larger than b+c.

Example 2

However, suppose a=10; b=9; c=8; d=1.

Note that $a > b > c > d$ ( $10 > 9 > 8 > 1$ ) but that $a+d=(10)+(1)=11$ , and $b+c=(9)+(8)=17$ , so a+d is smaller than b+c.

So, in one example, a+d is bigger, and in the other, a+d is smaller. Therefore, there is no way to tell which of a+d or b+c is larger from only the given information.

5 0

2 years ago

Which number is irrational? A. square root of 5 B. 0.777... C. 0.454545... D. 0.3

Veronika [31]

Answer:

Step-by-step explanation:

The square root of 5 is irrational because it cannot be expressed as a fraction.

Meanwhile, all 3 other answer choices are not irrational because they can be put into fraction form.

7 0

3 years ago

Read 2 more answers