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crimeas [40]
3 years ago
14

Claire sat a spanish test and a french test In the spanish test she scored 27 out of 32 In the french test she scored 19 out of

21 In which test did she do better?
Mathematics
1 answer:
balu736 [363]3 years ago
7 0

Answer:

French test

Step-by-step explanation:

We first calculate the scores as percentages:

#Spanish test:

=\frac{score}{total}\times 100\%\\\\\\=\frac{27}{32}\times 100\%\\\\=84.38\%

#For the French test, her percentage is:

=\frac{score}{total}\times 100\%\\\\=\frac{19}{21}\times 100\%\\\\=90.48\%

Since, 90.48$>84.38%, Claire did better in the French test.

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What is the quotient when (x+3) is divided into the polnomial 2x^2+x-15
Alika [10]

Answer:

2x-5

remainder of 0

Step-by-step explanation:

Check the image

7 0
3 years ago
149 cars are waiting to take a ferry across the channel. Each ferry can only hold 18 cars. How many cars will be on the last fer
balandron [24]

149 \div 18 = x
8r5 = x
There will be 9 trips the ferry makes and on the last trip there will be 5 cars on the ferry.

5 0
3 years ago
TWO TRUTHS ONE LIE
Ivenika [448]

Answer:

(3) A"B"C" can be mapped onto A'B'C' by rotating it 180 degrees

Step-by-step explanation:

well, the other two are true, so that only leaves one option, sorry if this is wrong

5 0
2 years ago
A 40-m-long chain hangs vertically from a cylinder attached to a winch. Assume there is no friction in the system and the chain
daser333 [38]

Answer:

a) W₁ = 78400 [J]

b)Wt = 82320 [J]  

Step-by-step explanation:

a) W = ∫ f*dl      general expression for work

If we have a chain with density of 10 Kg/m, distributed weight would be

9.8 m/s² * 10 kg   = mg

Total length of th chain is 40 m, and the function of y at any time is

f(y) = (40 - y ) mg   where ( 40 - y ) is te length of chain to be winded

At the beggining we have to wind 40 meters   y = 0 at the end of the proccess  y = 40 and there is nothing to wind then:

f(y) = mg* (40 - y )

W₁ =  ∫f(y) * dy    ⇒ W₁ = ∫₀⁴⁰ mg* (40 - y ) dy  ⇒ W₁ = mg [ ∫₀⁴⁰ 40dy - ∫₀⁴⁰ ydy

W₁ = mg [ 40*y |₀⁴⁰   -  1/2 * y²  |₀⁴⁰    ⇒  W₁ = mg* [ 40*40 - 1/2 (40)² ]

W₁ = mg * [1/2]     W₁ = 10*9,8* ( 800 )

W₁ = 78400 [J]

b) Now we can calculate work to do if we have a 25 block and the chain is weightless

W₂ = ∫ mg* dy     ⇒    W₂  = ∫₀⁴⁰ mg*dy   ⇒    W₂  = mg y |₀⁴⁰

W₂ = mg* 40   = 10*9.8* 40  

W₂ = 3920 [J]

Total work

Wt = W₁  +  W₂        ⇒    Wt = 78400 + 3920

Wt = 82320 [J]

6 0
3 years ago
I dont get it?? how do i set it up?? im so... confused?? can i get some helpm
snow_tiger [21]

Well, you need a diagram (see attached).

Since angle S = angle T then

9x -11 = 7x -3  ......  2x = 8 ........ x = 4

RS = RT = 4

There must be some more information that can't be seen


5 0
3 years ago
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