Answer:
$25,695
Step-by-step explanation:
You can calculate the price of the car in 2000 using the formula to calculate the future value:
FV=PV(1+r)^n
FV= future value
PV= Present value: $7,500
i= rate: 5.5%
n= number of years: 2000-1977= 23
FV= 7,500*(1+0.055)^23
FV= 7,500*(1.055)^23
FV= 7,500*3.426
FV= 25,695
According to this, the approximate value of the car at the time of the auction is $25,695.
Answer:
0.3285
Step-by-step explanation:
This problem involves Geometric probability distribution because experiment is repeated different number of times until success is achieved.
we have to find P(X≥4). It can be written as P(X≥4)=1-P(X<4)=1-P(X≤3)
P(X≤3)=?
Using Geometric probability distribution
P(X=n)=p^x*q^n-1
P(X≤3)=P(X=1)+P(X=2)+P(X=3)
Here p=0.31,
P(X≤3)=0.31^1*0.69^0+0.31^2*0.69^1+0.31^3*0.69^2)=0.6715
P(X≥4)=1-P(X≤3)=1-0.6715=0.3285
The probability that the first strawberry candy chosen from a bag will be, at LEAST, the fourth candy chosen overall is 32.85%.
Answer:
It means that you have a function that every time you input a value of x gives you 3 . If x=45 then y=3 ...if x=−1.234 then, again, y=3 and so on!
Step-by-step explanation:
I believe using the equation v=lwh the answer would be 420ft^3.
