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vaieri [72.5K]
3 years ago
12

A six-sided die is rolled two times. What is the theoretical fractional probability that the first number is even and the second

number is odd?​
Mathematics
1 answer:
Nostrana [21]3 years ago
6 0

Answer:

The theoretical probability that the first number is even and the second number is odd is \frac{1}{4}.

Step-by-step explanation:

Since each dice has six sides, and there are two die, the total amount of different outcomes are 6^2 or 36. The probability of getting an even number on the first roll is \frac{3}{6} or \frac{1}{2}, and the probability of getting an odd number on the second roll is also \frac{3}{6} or \frac{1}{2}, so the probability of getting an even number on the first roll and an odd number on the second roll is \frac{1}{2} * \frac{1}{2} = \frac{1}{4}.

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Answer:

z=\frac{0.75 -0.72}{\sqrt{\frac{0.72(1-0.72)}{900}}}=2.00  

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Step-by-step explanation:

Information given

n=900 represent the random sample selected

\hat p=0.75 estimated proportion of residents favored annexation

p_o=0.72 is the value that we want to test

represent the significance level

z would represent the statistic

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Hypothesis to test

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Null hypothesis:p\leq 0.72  

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The statistic for this case is given by:

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Replacing the data given we got:

z=\frac{0.75 -0.72}{\sqrt{\frac{0.72(1-0.72)}{900}}}=2.00  

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p_v= P(Z>2) =0.0228

Since the p value is lower than the significance level of 0.05 we have enough evidence to conclude that the true proportion of residents favored annexation is higher than 0.72 or 72%

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Step-by-step explanation:

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