The area of a triangle is 1/2(base x height) .
The two legs of this triangle are equal. If you position it properly,
one of them is the base, and the other one is the height.
Since it's a right triangle, A² + B² = C²
But A = B and C = 24 .
2A² = (24)²
A² = (24)² / 2
But since A=B, A² is also (base x height) of the triangle.
Area is just 1/2 of it.
Area = 1/2(24²/2) = (24)²/4 = (24/2)² = (12)² = <u>144</u> .
Answer:
Yes, PQR ~ TSV with a scale of 1 : 
Step-by-step explanation:
Yes the triangles are congruent for the statement given in option C
The scale 1 :
shows that the side lengths are proportional
PQ/TS = QR/SV
3
/6/
and that's simplified as 1/
Answer: 20880 seconds.
Step-by-step explanation:
9)
(y^-3)^6
y^-18
1/y^18
10)
(-x^6)^3
-x^18
11)
(q^9)^2
q^18
12)
(y^-5)^-10 y^10
y^50 • y^10
y^60