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ziro4ka [17]
2 years ago
5

Plz help me. will give brainliest!!

Mathematics
1 answer:
Nesterboy [21]2 years ago
6 0

Answer:

1. 110

2. 84

Step-by-step explanation:

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Solve.<br><br> m - 15 = 20<br><br> m =
Fittoniya [83]

\text{Hello There!}

\text{We are going to need to isolate the variable}

m - 15 = 20

\text{Add 15 to both sides.}

\text{We do this because we need to perform inverse operations to find} \text{the value of the variable.}

m - 15 + 15 = 20 + 15 = 35

\fbox{Therefore, your answer is going to be 35.}

\rule{300}{1.5}

7 0
3 years ago
Read 2 more answers
F(x) = (1/4)^x. for x = -3
Trava [24]
Plug in -3 for x into the equation.

(1/4)^-3

And solve

(1/4)^-3 = 64
7 0
2 years ago
Read 2 more answers
Which model best fits the set of data shown on this graph?
Blizzard [7]

Answer:

C

Step-by-step explanation:

Quadratic model is shaped like a "U", or a parabola

Quartic model is shaped like a "W", highest degree is 4 (x^4).

Linear model is a line.

Cubic model is x^3, shaped like a curvy snake.

Looking at the graph, it <em>clearly</em> shows a line. So, linear model is the answer.

C is the correct answer.

4 0
3 years ago
6. Write the following multiplications as exponential abbreviations.
romanna [79]

Answer:

6. A= 5^2      B= 7^4     C=2^3    D=9^5

7. A= i dont know           B= i dont know         C=5*5*5   D=i dont know

Step-by-step explanation:

4 0
3 years ago
A ball bounces back 0.6 of its height on every bounce. If a ball is dropped 200 feet, how high does it bounce the fifth bounce?
MissTica

It is asking you to slice off 40% of the bounce height in each subsequent bounce.


So you start with full height 1, that's n = 0 bounces. Then after n = 1 bounce the new height is .6. After the second bounce, n = 2, the height becomes .6 X .6 = .36. And after n = 3, we have .6 X .6 X .6 = .216


So by induction we see that h(n = 5) = .6^n = .6^5 = 0.07776 = .078 of its original height or H = .078*200 = 15.6 ft. after five bounces. ANS. 16.0 if rounded to the nearest tenth

:)


4 0
3 years ago
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