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3 years ago

2 1/3 + 3 2/4 = Fractions

Mathematics

2 answers:

Sauron [17]3 years ago

6 0

5 5/6 is the answer I think

Yuki888 [10]3 years ago

6 0

Step-by-step explanation:

2 1/3+3 2/4=7/3+14/4

=28/12+42/12 (common denominater)

=70/12

=5 10/12

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a square poster of length 3x is going to have a square painting centered on it. The length of the painting is 2x. the area of th

eduard

One way to solve this is to look at the size of the poster, and then subtract the size of the picture so you have the area that needs to be painted left.

Area of square poster - 3x × 3x = 9x^2
Area of painting - 2x × 2x = 4x^2

9x^2 - 4x^2 = 5x^2

The area is 5x^2

3 0

4 years ago

1. Suppose you have 62 toothpicks and a bunch of rubber bands.

ehidna [41]

Base-ten units are used to represent numbers in blocks

<h3>How to represent the bundle of toothpicks</h3>

The bundle is given as:

Bundle = 62

Rewrite as:

Bundle = 60 + 2

Express 60 as a product

Bundle = 6 * 10 + 2

See attachment for the drawing that represents the bundle

<h3>Ways to interpret the 6 in 62</h3>

The 6 in 62 can be interpreted in the following ways

Way 1: 6 tens
Way 2: 60

Read more about base-ten units at:

brainly.com/question/12386995

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2 years ago

Give the coordinates for point P in the kite below without using any variables

mart [117]

Answer: D. (-b,0)

applying coordinate geometry practice

the whole quiz >

1. b.

2. a.

3. c.

4. d.

5. c.

6. c.

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5 0

3 years ago

Read 2 more answers

After studying the diagram shown, Michael makes the following conclusions:

inn [45]

Answer:

Therefore, Michael concludes option C)

C) $(DA)^{2}=(DG)^{2}+(AG)^{2}$

Step-by-step explanation:

Given:

1. DG = 3 and the area of square DEFG is 9.

2. AG = 4 and the area of square GHIA is 16.

3. DA = 5 and the area of square ABCD is 25.

So we have,

$(DG)^{2}=3^{2}=9\\ \\(AG)^{2}=4^{2}=16\\\\(DA)^{2}=5^{2}=25\\$

Now Add DG² and AG² we get

$(DG)^{2}+(AG)^{2}=9+16=25=(DA)^{2}$

Which is also called as Pythagoras theorem i.e

$(\textrm{Hypotenuse})^{2} = (\textrm{Shorter leg})^{2}+(\textrm{Longer leg})^{2}$

Therefore, Michael concludes option C)

C) $(DA)^{2}=(DG)^{2}+(AG)^{2}$

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3 years ago

An ore ship is traveling west toward Duluth on Lake Superior at 18 miles per hour. The bearing of Split Rock Lighthouse is 285de

Luda [366]

<span>You are given an ore ship that is traveling west toward Duluth on Lake Superior at 18 miles per hour with a bearing of 285deg Split Rock Lighthouse. Also, after 1 hour the bearing of the lighthouse is 340deg. The distance between the ship and the lighthouse when the second bearing is determined is 35 miles.</span>

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3 years ago