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Viktor [21]
2 years ago
10

SOME BODY PLEEEASE HELP ME WITH THESE I need these completed by tonight PLLEEASEE7. Find the measures of the following to the

Mathematics
1 answer:
Reika [66]2 years ago
8 0

Step-by-step explanation:

7, HT= \sqrt{8^2 + 15^2} =17 cm

8, S = 1/2.AC.BC.sinC≈28,01 cm^2

9, S =1/2.SR.RT.sin R≈ 3615,7 m^2

Prove:

the area of the ABC triangles is S

sin A = BH/AB

S = 1/2 BH.AC=1/2 sinA.AB.AC=1/2*c*b*sinA

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Find thd <img src="https://tex.z-dn.net/?f=%5Cfrac%7Bdy%7D%7Bdx%7D" id="TexFormula1" title="\frac{dy}{dx}" alt="\frac{dy}{dx}" a
NARA [144]

x^3y^2+\sin(x\ln y)+e^{xy}=0

Differentiate both sides, treating y as a function of x. Let's take it one term at a time.

Power, product and chain rules:

\dfrac{\mathrm d(x^3y^2)}{\mathrm dx}=\dfrac{\mathrm d(x^3)}{\mathrm dx}y^2+x^3\dfrac{\mathrm d(y^2)}{\mathrm dx}

=3x^2y^2+x^3(2y)\dfrac{\mathrm dy}{\mathrm dx}

=3x^2y^2+6x^3y\dfrac{\mathrm dy}{\mathrm dx}

Product and chain rules:

\dfrac{\mathrm d(\sin(x\ln y)}{\mathrm dx}=\cos(x\ln y)\dfrac{\mathrm d(x\ln y)}{\mathrm dx}

=\cos(x\ln y)\left(\dfrac{\mathrm d(x)}{\mathrm dx}\ln y+x\dfrac{\mathrm d(\ln y)}{\mathrm dx}\right)

=\cos(x\ln y)\left(\ln y+\dfrac1y\dfrac{\mathrm dy}{\mathrm dx}\right)

=\cos(x\ln y)\ln y+\dfrac{\cos(x\ln y)}y\dfrac{\mathrm dy}{\mathrm dx}

Product and chain rules:

\dfrac{\mathrm d(e^{xy})}{\mathrm dx}=e^{xy}\dfrac{\mathrm d(xy)}{\mathrm dx}

=e^{xy}\left(\dfrac{\mathrm d(x)}{\mathrm dx}y+x\dfrac{\mathrm d(y)}{\mathrm dx}\right)

=e^{xy}\left(y+x\dfrac{\mathrm dy}{\mathrm dx}\right)

=ye^{xy}+xe^{xy}\dfrac{\mathrm dy}{\mathrm dx}

The derivative of 0 is, of course, 0. So we have, upon differentiating everything,

3x^2y^2+6x^3y\dfrac{\mathrm dy}{\mathrm dx}+\cos(x\ln y)\ln y+\dfrac{\cos(x\ln y)}y\dfrac{\mathrm dy}{\mathrm dx}+ye^{xy}+xe^{xy}\dfrac{\mathrm dy}{\mathrm dx}=0

Isolate the derivative, and solve for it:

\left(6x^3y+\dfrac{\cos(x\ln y)}y+xe^{xy}\right)\dfrac{\mathrm dy}{\mathrm dx}=-\left(3x^2y^2+\cos(x\ln y)\ln y-ye^{xy}\right)

\dfrac{\mathrm dy}{\mathrm dx}=-\dfrac{3x^2y^2+\cos(x\ln y)\ln y-ye^{xy}}{6x^3y+\frac{\cos(x\ln y)}y+xe^{xy}}

(See comment below; all the 6s should be 2s)

We can simplify this a bit by multiplying the numerator and denominator by y to get rid of that fraction in the denominator.

\dfrac{\mathrm dy}{\mathrm dx}=-\dfrac{3x^2y^3+y\cos(x\ln y)\ln y-y^2e^{xy}}{6x^3y^2+\cos(x\ln y)+xye^{xy}}

3 0
2 years ago
Describe the scene of my first rehearsal in 1st grade
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Answer:

that was when I was in 1st grade. I was quite confused and didn't know what to do. We rehearsed first. I made a lot of mistakes but everything was fine until I got on stage. I think when I finished performing, it was my proudest time

6 0
2 years ago
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Please answer all of the questions and if u are correct I will give u brainliest ;) xoxo &lt;3
garik1379 [7]

Answer:

the answer for the 2nd question is 1/4

Step-by-step explanation:

i took the test

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2 years ago
What are both of these shaded as?
Sedaia [141]

Answer:

1 whole and 15/100= <em><u>1.15</u></em>

Step-by-step explanation:

The first box is 1 whole, in total there are 100 squares. All u need to do is count the number of squares

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Partial product of 563 x 410
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The awnse is 230,830
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