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2 years ago

SOME BODY PLEEEASE HELP ME WITH THESE I need these completed by tonight PLLEEASEE7. Find the measures of the following to the

Mathematics

1 answer:

Reika [66]2 years ago

8 0

Step-by-step explanation:

7, HT= $\sqrt{8^2 + 15^2}$ =17 cm

8, S = 1/2.AC.BC.sinC≈28,01 cm^2

9, S =1/2.SR.RT.sin R≈ 3615,7 m^2

Prove:

the area of the ABC triangles is S

sin A = BH/AB

S = 1/2 BH.AC=1/2 sinA.AB.AC=1/2*c*b*sinA

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.Bryan was given the equation y= -5x+3. He says the rate of change is 3 and the initial value is -5. Is Bryan correct? If not, c

Mekhanik [1.2K]

Answer:

Correct rate of change is -5; correct initial value is 3.

Step-by-step explanation:

The rate of change is the coefficient of the x term, which here is -5. So Bryan has the rate of change wrong.

The initial value of the function is found by letting x = 0. Here, we get

y = -5(0) + 3, or y = b = 3. The initial value is 3, not -5.

8 0

2 years ago

PLEASE HELP<br> Evaluate 6 + 10v – 8w when v=4 & w= -2

BabaBlast [244]

Answer:

6 + 10v – 8w = 62

Step-by-step explanation:

Given the expression

6 + 10v – 8w

w=-2

substituting the values in the expression

6 + 10v – 8w = 6 + 10(4) - 8(-2)

= 6 + 40 + 16

= 62

5 0

2 years ago

Can someone please answer and explain to me

gtnhenbr [62]

Answer:

30 degrees

Step-by-step explanation:

USE the sine function to determine S. Set up the equation:

sine(S) = 1/2 -->

S = Sine^-1(1/2) -->

S = 30 degrees

3 0

3 years ago

Read 2 more answers

The number of typing errors made by a typist has a Poisson distribution with an average of seven errors per page. If more than s

Aleks [24]

Answer:

0.599 is the probability that a randomly selected page does not need to be retyped.

Step-by-step explanation:

We are given the following in the question:

The number of typing errors made by a typist has a Poisson distribution.

$\lambda =7$

The probability is given by:

$P(X =k) = \displaystyle\frac{\lambda^k e^{-\lambda}}{k!}\\\\ \lambda \text{ is the mean of the distribution}$

We have to find the probability that a randomly selected page does not need to be retyped

P(less than or equal to 7 mistakes in a page)

$P( x \leq 7) = P(x =1) + P(x=1) +...+ P(x=6) + P(x = 7)\\\\= \displaystyle\frac{7^0 e^{-7}}{0!} + \displaystyle\frac{7^1 e^{-7}}{1!} +...+ \displaystyle\frac{7^6 e^{-7}}{6!} + \displaystyle\frac{7^7 e^{-7}}{7!} \\\\= 0.59871\approx 0.599$

Thus, 0.599 is the probability that a randomly selected page does not need to be retyped.

4 0

3 years ago

The level of nitrogen oxides (NOX) in a exhaust of cars of a particular model varies normally with mean 0.25 grams per miles and

antoniya [11.8K]

Answer:

a) 15.87% probability that a single car of this model fails to meet the NOX requirement.

b) 2.28% probability that the average NOX level of these cars are above 0.3 g/mi limit

Step-by-step explanation:

We use the normal probability distribution and the central limit theorem to solve this question.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , a large sample size can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$