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2 years ago

12

Describe the location of the point having the following coordinates.

1 answer:

alex41 [277]2 years ago

6 0

Answer:

a graph can be divided into 4 quadrants.

a zero abscissa, means the point lies on the origin.

a negative ordinate means the point lies on the y axis in the third and fourth quadrants.

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Probability help!!!!!

nirvana33 [79]

Let A be the event $A=\{choosing \;an \;odd \;number\}$ and B be the vent $B=\{choosing \;an \;even \;number\}$ . Since the intersection of the events $A\cap B=\phi$ , the events A and B are mutually exclusive.

The number is either odd or even. Since $P(A)+P(B)=1$ , the events are mutually exclusive and exhaustive.

Correct choice is "the number is either odd or even".

7 0

3 years ago

7 1/6 = 5 2/5 + p<br><br> p = ???

Crank

$\huge\textbf{Hey there!}$

$\mathbf{7\dfrac{1}{6} = 5\dfrac{2}{5} + p}$

$\rightarrow\mathbf{7 \dfrac{1}{6} = 5\dfrac{2}{5} + p}$

$\mathbf{\rightarrow p + 5\dfrac{2}{5}= 7\dfrac{1}{6}}$

$\mathbf{\rightarrow {p + \dfrac{27}{5}=\dfrac{43}{6}}}$

$\text{SUBTRACT }\rm{\dfrac{27}{5}}\text{ to BOTH SIDES}$

$\mathbf{p + \dfrac{27}{5} - \dfrac{27}{5} = \dfrac{43}{6}- \dfrac{27}{5}}$

$\text{CANCEL out: }\rm{\dfrac{27}{5} - \dfrac{27}{5}}\text{ because it gives you 0}$

$\text{KEEP: }\rm{\dfrac{43}{6} - \dfrac{27}{5}}\text{ because it help solve for the p-value}$

$\text{NEW EQUATION: }\rm{p = \dfrac{43}{6} - \dfrac{27}{5}}$

$\large\textsf{SIMPLIFY IT!}$

$\mathbf{p = \dfrac{53}{30} \approx p = 1\dfrac{23}{30}}$

$\huge\boxed{\textsf{Therefore, your answer is: \boxed{\mathsf{p = 1\dfrac{23}{30}}}}}\huge\checkmark$

$\huge\textbf{Good luck on your assignment \&}\\\huge\textbf{enjoy your day!}$

~ $\frak{Amphitrite1040:)}$

3 0

2 years ago

Read 2 more answers

Divide and express your answer to lowest term

musickatia [10]

Step-by-step explanation:

3/4:2/5=3/4×5/2=15/8

3/8 ÷ 2/12=3/8 ×12/2=36/16=9/4

8 0

2 years ago

Which equations are equal to this equation Select all that apply. 1/4(8x+56)=20

Zanzabum

A and d are the answers

4 0

2 years ago

Two goals post are 8m apart. A footballer is 34m from one and 38m from the other. Within what angle must he kick the ball if he

dmitriy555 [2]

Answer:

11.06°

Step-by-step explanation:

The law of cosines can be used to find the angle. The sides adjacent to that angle are a=34, b=38, and the side opposite is c=8. Then the angle is found from ...

c² = a² +b² -2ab·cos(C)

cos(C) = (a² +b² -c²)/(2ab)

C = arccos((a² +b² -c²)/(2ab))

C = arccos((34² +38² -8²)/(2·34·38)) = arccos(317/323)

C ≈ 11.06°

From the footballer's viewpoint, the goal posts are 11.06° apart.

4 0

3 years ago