Given:
The figure of a rhombus QRST.
To find:
A. The value of x.
B. The measure of angle RQP.
Solution:
A. We need to find the value of x.
We know that the diagonals of a rhombus are perpendicular bisectors. It means the angles on the intersection of diagonals are right angles.
[Right angle]
Divide both sides by 5.
Therefore, the value of x is 15.
B. We need to find the measure of angle RQP.
From the given figure, it is clear that

Putting
, we get



Therefore, the measure of angle RQP is 33 degrees.
5x+34=-2(1-7x)
Steps:
5x+34=-2+14x
5x+34-14x= -2
-9x + 34= -2
-9x = -2-34
-9x = -36
X= -36/-9
Answer: x= 4
Answer:
because it can be written in the <u>form</u><u> </u>of p/q
Where p and q are integers, and q is <u>not</u> equal to zero.
Answer: the answer is
=3
−19x−14
Step-by-step explanation: (x−7)(3x+2)
=(x+−7)(3x+2)
=(x)(3x)+(x)(2)+(−7)(3x)+(−7)(2)
=3x2+2x−21x−14
=3x2−19x−14
Hmm if I'm not mistaken, is just an "ordinary" annuity, thus
![\bf \qquad \qquad \textit{Future Value of an ordinary annuity} \\\\ A=pymnt\left[ \cfrac{\left( 1+\frac{r}{n} \right)^{nt}-1}{\frac{r}{n}} \right] \\\\\\](https://tex.z-dn.net/?f=%5Cbf%20%5Cqquad%20%5Cqquad%20%5Ctextit%7BFuture%20Value%20of%20an%20ordinary%20annuity%7D%0A%5C%5C%5C%5C%0AA%3Dpymnt%5Cleft%5B%20%5Ccfrac%7B%5Cleft%28%201%2B%5Cfrac%7Br%7D%7Bn%7D%20%5Cright%29%5E%7Bnt%7D-1%7D%7B%5Cfrac%7Br%7D%7Bn%7D%7D%20%5Cright%5D%0A%5C%5C%5C%5C%5C%5C)