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Wittaler [7]
2 years ago
12

Roses normally cost $19.00 a dozen, but for Valentine's Day the price goes up to $35.00. What is the difference in price, includ

ing 7% tax?
Mathematics
1 answer:
JulijaS [17]2 years ago
4 0

Answer:

$17.12

Step-by-step explanation:

First let's find the normal cost with tax

7/100*19=133/100=$1.33

$19+$1.33=$20.33

Now we find the cost with tax for the Valentine's Day price

7/100*35=$2.45

$35+$2.45=$37.45

Now we subtract the normal cost from the Valentine's Day price

$37.45-$20.33=$17.12

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2 years ago
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7 0
3 years ago
Read 2 more answers
Find the shortest distance, d, from the point (5, 0, −6) to the plane x + y + z = 6.
DENIUS [597]

Answer:

\frac{7}{\sqrt{3}}

Step-by-step explanation:

The shortest distance d, of a point (a, b, c) from a plane mx + ny + tz = r is given by:

d = |\frac{(ma + nb + tc - r)}{\sqrt{m^2 + n^2 + t^2}} |                   --------------------(i)

From the question,

the point is (5, 0, -6)

the plane is x + y + z = 6

Therefore,

a = 5

b = 0

c = -6

m = 1

n = 1

t = 1

r = 6

Substitute these values into equation (i) as follows;

d = |\frac{((1*5) + (1*0) + (1 * (-6)) - 6)}{\sqrt{1^2 + 1^2 + 1^2}} |

d = |\frac{((5) + (0) + (-6) - 6)}{\sqrt{1 + 1 + 1}} |

d = |\frac{(-7)}{\sqrt{3}} |

d = \frac{7}{\sqrt{3}}

Therefore, the shortest distance from the point to the plane is  d = \frac{7}{\sqrt{3}}

5 0
3 years ago
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2 years ago
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