Question

What is the vertex of the quadratic function f(x)=3(x-5)^2+4???

Answer 1

Answer:

Vertex: (5, 4)

Step-by-step explanation:

Quadratic Transformations Equation: f(x) = a(bx - h)² + k

a - vertical shrink/stretch

b - horizontal shrink/stretch

h - horizontal movement left/right

k - vertical movement up/down

h, k - vertex

Answer 2

Answer:

5,4

Step-by-step explanation:

3(x-5)^2+4

3(x^2-10x+25)+4

3x^2-30x+75+4

3x^2-30x+79

now,

comparing with ax^2+bx+c

a=3

b=-30

c=79

for x, -b/2a

= -(-30)/2*3

=30/6

=5

replacing x

3x^2+bx+c

3*5^2+(-30)*5+79

3*25-150+79

75+79-150

154-150

4

the vertex are(x,y)

(5,4)