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3 years ago

-1.32+x=1 -1 -1 Not sure about this??

Mathematics

1 answer:

Ipatiy [6.2K]3 years ago

7 0

Answer:

x=2.32

Step-by-step explanation:

-1.32+x=1

add 1.32 to both sides

1.32 cancels itself out

so you are left with x=2.32

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Work out the difference between 16/18 and 4/18

Natali5045456 [20]

Answer:

the answer is 12/18

Step-by-step explanation:

16/18 - 4/18=12/18

common multiples of 18

18: 36 54 72 90 108 126 144 162 180

5 0

4 years ago

What is the side length of the eectagkes

dedylja [7]

1. 5 in and 1/3 in: Area = 5/3 in^2

2. 5 in and 4/3 in: Area= 20/3 in^2

3. 5/2 in and 4/3 in: Area=10/3 in^2

4. 7/6 in and 6/7 in: Area = 1 in^2

Step-by-step explanation:

1. 5 in and 1/3 in

Here,

$Let\\l=5\\w=\frac{1}{3}\\Area=l*w\\=5*\frac{1}{3}\\=\frac{5}{3}\ in^2$

2. 5 in and 4/3 in

Here,

$l= 5\ in\\w=\frac{4}{3}\ in\\Area=l*w\\=5*\frac{4}{3}\\=\frac{20}{3}\ in^2$

3. 5/2 in and 4/3 in

$let\\l=\frac{5}{2}\\w=\frac{4}{3}\\Area= \frac{5}{2}*\frac{4}{3}\\=\frac{20}{6}=\frac{10}{3}\ in^2$

4. 7/6 in and 6/7 in

Let

$l=\frac{6}{7}\\w=\frac{7}{6}\\Area=l*w\\=\frac{6}{7}*\frac{7}{6}\\=1\ in^2$

Hence,

1. 5 in and 1/3 in: Area = 5/3 in^2

2. 5 in and 4/3 in: Area= 20/3 in^2

3. 5/2 in and 4/3 in: Area=10/3 in^2

4. 7/6 in and 6/7 in: Area = 1 in^2

Keywords: Rectangle, Area

Learn more about rectangles at:

#LearnwithBrainly

8 0

4 years ago

What is the multiplier for 5/7=30/42 please help

horsena [70]

Answer:

The multiplier is 1

specifically:

$\frac{6}{6}$

Step-by-step explanation:

Let the multiplier be k

Then,

$\frac{5}{7} \times k = \frac{30}{42}$

We multiply both sides by 7/5

$\frac{7}{5} \times \frac{5}{7} k = \frac{30}{42} \times \frac{7}{5}$

$k = \frac{6}{6}$

We can simplify this further to get 1.

This implies that:

$\frac{5}{7} \times \frac{6}{6} = \frac{30}{42}$

Hence the multiplier is 1.

8 0

3 years ago

What is 6% of 20,200

chubhunter [2.5K]

The answer of 6% of 20,200 is 1,212

6 0

3 years ago

At the beginning of the months, a consumer had $437.52 of in his bank account. During he made deposits of $256 and $217.14 of $8

alexdok [17]

Question:

At the beginning of the months, a consumer had $437.52 of in his bank account. During which he made deposits of $80, $256 and $217.14 and write checks of $115.98 and $108.90 - What balance left?

Answer:

The customer's balance is $765.78

Step-by-step explanation:

Given

Start Amount = $437.52

Deposits = $80, $256 and $217.14

Withdrawals (Checks) = $115.98 and $108.90

Required

Determine his balance

We start by calculating the total deposits made by the customer

$Total\ Deposits = \$80 + \$256 + \$217.14$

$Total\ Deposits = \$553.14$

Next, we calculate the total withdrawals (checks)

$Total\ Withdrawals = \$115.98 + \$108.90$

$Total\ Withdrawals = \$224.88$

At this point, we can now calculate the customer's balance as follows;

$Balance =Start\ Amount + Total\ Deposits - Total\ Withdrawals$

$Balance = \$437.52+ \$553.14 -\$224.88$

$Balance = \$765.78$

Hence, the customer's balance is $765.78

3 0

3 years ago