All categories

2 years ago

Please help me i am in need of serious help or ill flunk :(

Mathematics

1 answer:

lina2011 [118]2 years ago

8 0

co.op

interest = principle * rate * time in years

8000*0.09*1= 720$

total owed =

principle + interest

8000+720= 8720$

bank

interest = principle * rate * time in years

interest = principle * rate * time in years8000*0.06*1= 480$

principle + interest

8000+480= 8480$

......

Bank A

interest = 1500*2*0.18= 540$

total owed = 1500+540= 2040$

Bank B

compound interest =

1500(1+0.12)^2

compound interest= 1881.6

total owed = 1500+1881.6= 3381.6$

she should choose Bank A less total owed

she'll have to pay the bank 2040$

You might be interested in

A wedding ring costs £13000. Work out the price after a 11% increase

olga2289 [7]

When £13000 is increased by 11% the new value becomes to £14430

7 0

2 years ago

Read 2 more answers

4/5 of a number is 32

andrew11 [14]

Answer:

x = 40

Step-by-step explanation:

Step 1: Write out an equation

4/5(x) = 32

Step 2: Solve by dividing both sides by 4/5

x = 32/(4/5)

<em>Use KCF (Keep Change Flip) if you do not have a calc.</em>

x = 40

6 0

3 years ago

Read 2 more answers

g Suppose a factory production line uses 3 machines, A, B, and C for making bolts. The total output from the line is distributed

Vladimir [108]

Answer:

The probability that it came from A, given that is defective is 0.362.

Step-by-step explanation:

Define the events:

A: The element comes from A.

B: The element comes from B.

C: The element comes from C.

D: The elemens is defective.

We are given that P(A) = 0.25, P(B) = 0.35, P(C) = 0.4. Recall that since the element comes from only one of the machines, if an element is defective, it comes either from A, B or C. Using the probability axioms, we can calculate that

$P(D) = P(A\cap D) + P(B\cap D) + P(C\cap D)$

Recall that given events E,F the conditional probability of E given F is defined as

$P(E|F) = \frac{P(E\cap F)}{P(F)}$ , from where we deduce that

$P(E\cap F) = P(E|F)P(F)$ .

We are given that given that the element is from A, the probability of being defective is 5%. That is P(D|A) =0.05. Using the previous analysis we get that

$P(D) = P(A)P(D|A)+P(B) P(D|B) + P(C)P(D|C) = 0.05\cdot 0.25+0.04\cdot 0.35+0.02\cdot 0.4 = 0.0345$