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Virty [35]
3 years ago
11

What is the value of this expression when g = -3.5?

Mathematics
1 answer:
Margaret [11]3 years ago
8 0

g = -3,5

8 - |2g - 5| = 8 - |2 · (-3,5) - 5| =

= 8 - |-7 - 5| = 8 - |-12| = 8 - 12 = <u>-</u><u>4</u>

You might be interested in
Seven and thirty twp hundreths plus two and one tenth times two and seven tenths minus 18a
alexdok [17]
Answer:  Write the expression as:

" 70 \frac{32}{100} +
                         2\frac{1}{10} * 2\frac{7}{10 − 18a " ; 
______________________________________________________
or;  write as:
______________________________________________________
           " 70.32  + (2.1) * (2.7)  − 18a " ; 
______________________________________________________

To simplify:
______________________________________________________

  Using "PEDMAS" (the "order of operations") ; 

the "multiplication" comes first; 

So:  →  "(2.1) * (2.7) =  5.67 " .

And rewrite:
______________________________________________________
 " 70.32  + 5.67 − 18a " .

Now:  " 70.32 + 5.67 = 75.99 " ; 

So, we can the final simplified expression as:
______________________________________________________
   " 75.99  −  18a " ;  

or; write as:  " 75\frac{99}{100}  −  18a " .
______________________________________________________
7 0
3 years ago
Simplify the expression (-8/15)+(1/15)
Mice21 [21]
If it is fractions then the answer is -7/15. Think of as 8/15 - 1/15 except the answer is a negative number

4 0
3 years ago
2x + 7 = 27 or 3 + 3x = 30
Leokris [45]

Step-by-step explanation:

2x + 7 = 27 OR 3 + 3x = 30.

2x = 27 - 7 OR 3x = 30 - 3

2x = 20 OR 3x = 27

x = 20/2 OR x = 27/3

x = 10 OR x = 9

5 0
2 years ago
Which term can be described as an if-then statement ?
tankabanditka [31]
It would most likely be D theory 
8 0
3 years ago
PLEASE HELP?! IM SO CONFUSED!!
seropon [69]

Answer:

C.

Step-by-step explanation:

-3 7/8 rounds down to -4

4.63 rounds up to 5

-4 x 6 + 5

-24 + 5

-19

her answer (-19.14) also rounds to -19

So yes, it is reasonable and the correct response is C.

8 0
1 year ago
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