10x^3 is the greatest common factor
Total tickets sold = 159
Total sales = $1100.60
Child admission = $5.20
Adult admission = $8.90
Assumed all 159 tickets are Child admission tickets
Total sales = 159 x 5.2 = $826.80
Difference in amount = $1100.60 - $826.80 = $273.80
The difference must be contributed by the Adult Admission Tickets, which has a difference of $8.90 - $5.20 = $3.70
$273.80 ÷ $3.70 = 74 adult tickets
159 - 74 = 85 child tickets
To help you with this topic, I would suggest you revise probability trees.
P(train arriving) = 0.8
P(train arriving on time) = 0.84
P(train arriving late) = 0.86
0.8 x 0.86 = 0.688
Answer: 0.688
Hope it helped :)
Stevie has 25marbles
Freddie's has 25x2:50marbles
Danny has 50+5:55marbles
