Graph y= –3x+4 k12 im practing for a test can i get this in picture form
1 answer:
<em>Figure represented the line y = -3x+4</em>
Step-by-step explanation:
Given y=-3x+4 is equation of line
In order to graph the line, we need atleast two points
Now, When x = 0, y=?
y = -3x+4
y = -3(0) +4
y = 4
Point we get A(0,4)
Now, When x = 1, y=?
y = -3x+4
y = -3(1)+4
y = -3+4 = 1
Point we get B(1,1)
On graph, Locate points A(0,4) and B(1,1)
Draw a line passing through both of the points at once.
Figure is shown for your reference.
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Answer:
slope = 2
Step-by-step explanation:
In place of t, or theta, I'm going to utilize x instead. So the equation is -3*cos(x) = 1. Get everything to one side and we have -3*cos(x)-1 = 0
Let f(x) = -3*cos(x)-1. The goal is to find the root of f(x) in the interval [0, 2pi]
I'm using the program GeoGebra to get the task done of finding the roots. In this case, there are 2 roots and they are marked by the points A and B in the attachment shown
A = (1.91, 0)
B = (4.37, 0)
So the two solutions for theta are
theta = 1.91 radians
theta = 4.37 radians
Let f(x) = -3*cos(x)-1. The goal is to find the root of f(x) in the interval [0, 2pi]
I'm using the program GeoGebra to get the task done of finding the roots. In this case, there are 2 roots and they are marked by the points A and B in the attachment shown
A = (1.91, 0)
B = (4.37, 0)
So the two solutions for theta are
theta = 1.91 radians
theta = 4.37 radians