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adoni [48]
4 years ago
7

Hey hey hey bye bye bye

Mathematics
1 answer:
Jet001 [13]4 years ago
7 0
Hey times three bye times three
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melissa drew a scale drawing of a city. a neighborhood park is 36 inches wide in the drawing. the actual park is 60 yards wide.
SashulF [63]

The scale of the drawing by using proportion is 3 : 5.

According to the given question.

Melissa drew a scale drawing of a city.

The width of the park in the drawing is 36 inches.

And the actual width of the park is 60 yards.

As we know that, a proportion is a fraction of a total amount, and the measures are related using a rule of three.

Therefore, the scale of the drawing by using proportion

= 36iches/ 60 yards

= 3/5

= 3 : 5

Hence, the scale of the drawing by using proportion is 3 : 5.

Find out more information about scale here:

brainly.com/question/28060140

#SPJ4

5 0
2 years ago
I need the answers for all of these! Please help
mihalych1998 [28]
What grade give  this kind of work
7 0
3 years ago
HELP ASAP. a kite has diagonals of 18 inches and 21 inches as seen below. what is the perimeter of the kite
timofeeve [1]

Answer:

78 inches

Step-by-step explanation:

perimeter of a kite formula: 2(a+b)

a= 18 inches

b= 21 inches

2(18+21)

2(39)

78 inches

8 0
3 years ago
Using the digits 1 to 9, at most one time each, fill in the blanks to make two different pairs of two-digit numbers that have a
agasfer [191]
Do you mean no repeating numbers within the two sets? Because if so, I don't think it's possible.

I started by trying to figure out what the numbers in the tenths place should be. I used subtraction: 71 - ___ = ____. If you try it out, you can't subtract anything with a 6, 7, 8, or 9 in the tenths place because it will leave you with 11 (a repeating digit number), 10 (has a 0), or less (1-digit numbers). Also, a 3 cannot go into the tenths place because when you do 71 - 3_ , your answer will always begin with a 3 (problem because the 3 repeats), or it will contain a 0. 

Therefore, the numbers left for the tenths place are: 1, 2, 4, and 5. 1 and 5 pair up, leaving 4 and 2.
71 - 5_ = 1_   and 71 - 4_ = 2_.

Then, I tried to figure out what numbers go in the ones place. That lead me to realize they act in pairs. The pairs possible in the ones place are 2 and 9, 3 and 8, 4 and 7, 5 and 6. These numbers always go together to result with the final "1" in the "71". Using this information, I looked at the numbers I already used: 1, 2, 4, and 5. Now, looking at the pairs, I eliminated the pairs containing a number already used. This leaves me with only one pair: 3 and 8. Obviously, you need two more pairs to solve the problem, which leads me to my point of saying: This problem is impossible to solve.

I really hope someone can prove me wrong! But this is the solution I have reached for now. :)
4 0
3 years ago
Which problem can be represented by the equation 49y−8=89?
sasho [114]
The first one is the answer
4 0
3 years ago
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