Answer:
- There is no significant evidence that p1 is different than p2 at 0.01 significance level.
- 99% confidence interval for p1-p2 is -0.171 ±0.237 that is (−0.408, 0.066)
Step-by-step explanation:
Let p1 be the proportion of the common attribute in population1
And p2 be the proportion of the same common attribute in population2
: p1-p2=0
: p1-p2≠0
Test statistic can be found using the equation:
where
- p1 is the sample proportion of the common attribute in population1 (
)
- p2 is the sample proportion of the common attribute in population2 (
)
- p is the pool proportion of p1 and p2 (
)
- n1 is the sample size of the people from population1 (30)
- n2 is the sample size of the people from population2 (1900)
Then
≈ 2.03
p-value of the test statistic is 0.042>0.01, therefore we fail to reject the null hypothesis. There is no significant evidence that p1 is different than p2.
99% confidence interval estimate for p1-p2 can be calculated using the equation
p1-p2±
where
- z is the z-statistic for the 99% confidence (2.58)
Thus 99% confidence interval is
0.533-0.704±
≈ -0.171 ±0.237 that is (−0.408, 0.066)
Answer:
12
Step-by-step explanation:
this equation is in slope intercept form which is
y=mx+b
you just have to remember that m is your slope and b is your y intercept
therefore, the y intercept is 12
Answer:
t =17 years
Step-by-step explanation:
The formula for interest
A = P(1+ r/n)^ nt
where a is the amount in the account , p is the principal, r is the rate, n is the number of times compounded per year and t is the time in years
Substituting in what we know
690 = 460 ( 1+ .024/365)^ 365t
690/460 = ( 1+ .024/365)^ 365t
1.5 = ( 1+ .024/365)^ 365t
Taking the log of each side
log(1.5) = 365t log( 1+ .024/365))
Dividing each side by( 1+ .024/365)
log(1.5)/ log( 1+ .024/365) = 365t
divide each side by 365
1/365 log(1.5)/ log( 1+ .024/365) =t
t =16.8949
To the nearest year
t =17