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Igoryamba
3 years ago
8

What is the slope of the line that passes through (-12, -5) and (0, -8)?

Mathematics
1 answer:
Lady bird [3.3K]3 years ago
8 0

Answer:

-3/12

Step-by-step explanation:

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Find the intervals on which the function is increasing or decreasing.
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To solve this, you have to know that the first derivative of a function is its slope. When an interval is increasing, it has a positive slope. Thus, we are trying to solve for when the first derivative of a function is positive/negative.

f(x)=2x^3+6x^2-18x+2
f'(x)=6x^2+12x-18
f'(x)=6(x^2+2x-3)
f'(x)=6(x+3)(x-1)
So the zeroes of f'(x) are at x=1, x=-3
Because there is no multiplicity, when the function passes a zero, he y value is changing signs.
Since f'(0)=-18, intervals -3<x<1 is decreasing(because -3<0<1)
Thus, every other portion of the graph is increasing.
Therefore, you get:

Increasing: (negative infinite, -3), (1, infinite)
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3 years ago
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Studentka2010 [4]
D 110, gimme that young brainlyest


6 0
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Please answer correctly !!!!!!! Will mark a lot of points !!!!!!!!
soldi70 [24.7K]

Answer:

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Step-by-step explanation:

3 0
2 years ago
A sphere is inscribed in a cube with a surface area of 216 square centimeters. What is the volume of the sphere
pentagon [3]

Answer:

V=298.5cm^3

Step-by-step explanation:

To find the volume of the sphere we need to know its radius.

And the radius can be found with the information we have about the surface area.

The formula for the surface area is as follows:

SA=4\pi r^2

from this formula we clear the radius r:

r^2=\frac{SA}{4\pi}\\ \\r=\sqrt{\frac{SA}{4\pi} }

and we substitute the known value of the surface area, and also the value of \pi:

r=\sqrt{\frac{216cm^2}{4(3.1416)} }\\ \\r=\sqrt{\frac{216cm^2}{12.5664} }\\ \\r=\sqrt{17.1887cm^2}\\ \\r=4.146cm

and now that we know the radius we find the volume:

V=\frac{4\pi r^3}{3} \\\\V=\frac{4(3.1416)(4.146cm)^3}{3}\\ \\V=\frac{895.521cm^3}{3}\\ \\V=298.5cm^3

the volume of the sphere is 298.5cm^3

7 0
3 years ago
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