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Crank
3 years ago
5

What is the square root of 1296??

Mathematics
1 answer:
Elden [556K]3 years ago
6 0
<span>The square root of 1296 is 36.</span>
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Solve each equation.<br> 7) 18 =-2+a<br> 8) -7= m - 12<br> 9) -8(7 + 7n)=-336<br> 10) -140=-7(-4+36)
lesya692 [45]

Answer:

7) a= 20

8) m= 5

9)n = 5

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Step-by-step explanation:

7) 18+2=-2+2+a

>> 20 = a >> a = 20

18 + 2 = 20 so that isolates the variable leaving a = 20

8) -7+12 = m -12+12

>>> 5 = m >> m = 5

-7 + 12 = 5 so that again isolates the variable leaving m = 5

9) <u>-8(7</u> + <u>7n</u>) = -336

>> -56+56 + -56n = -336+56

>>> -56n/-56 = -280/-56

>>>> n = 5

use distributive property, cancel out necessary numbers, isolate the variable. leaving n = 5.

10) -140 = <u>-7(-4 </u>+ <u>3b)</u>

>>  -140 = 28 - 21b >> -140-28 = -21b +28-28 ( flipped the numbers)

>>>  -168/-21 = -21b /-21

>>>> 8 = b >> b =8

Hope it helps!

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Ayuda, necesito operación y solución
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Suppose the circumference of a circle is 2pi what is its area?
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