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max2010maxim [7]
3 years ago
6

Show that the sum of two concave functions is concave. Is the product of two concave functions also concave?

Mathematics
1 answer:
spayn [35]3 years ago
8 0

Answer with explanation:

Let us assume that the 2 functions are:

1) f(x)

2) g(x)

Now by definition of concave function we have the first derivative of the function should be strictly decreasing thus for the above 2 function we conclude that

\frac{d}{dx}\cdot f(x)

Now the sum of the 2 functions is shown below

y=f(x)+g(x)

Diffrentiating both sides with respect to 'x' we get

\frac{dy}{dx}=\frac{d}{dx}\cdot f(x)+\frac{d}{dx}\cdot g(x)\\\\

Since each term in the right of the above equation is negative thus we conclude that their sum is also negative thus

\frac{dy}{dx}

Thus the sum of the 2 functions is also a concave function.

Part 2)

The product of the 2 functions is shown below

h=f(x)\cdot g(x)

Diffrentiating both sides with respect to 'x' we get

h'=\frac{d}{dx}\cdot (f(x)\cdot g(x))\\\\h'=g(x)f'(x)+f(x)g'(x)

Now we can see the sign of the terms on the right hand side depend on the signs of the function's themselves hence we remain inconclusive about the sign of the product as a whole. Thus the product can be concave or convex.

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Answer:

f(-5) = 23

Step-by-step explanation:

Step 1: Define

f(-5) = x = -5

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Step 2: Substitute

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Step 3: Evaluate

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Answer:

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Step-by-step explanation:

So it just looks like we need to use algebra to move everything around to get it in the form Ax + By = C

So, let's start with 9y = 12x + 0.2.  From standard form we have all terms wth variables on one side, so let's do that.  the right sie has both a variable term and non variable term, so let's get rid of the variable term.  The variable term is 12x, so to get rid of it you subtract 12x from both sides.

9y = 12x + 0.2

9y - 12x = 0.2

To make it exactly in standard form just rarrnge.

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Step-by-step explanation:

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