What the vertex and AOS if the equation is y=(x-2)^2-2
1 answer:
Answer:
See below.
Step-by-step explanation:
For y = a(x - b)^2 + c , the vertex is at (b, c) and the axis of symmetry is x = b.
So for y = (x-2)^2 - 2,
the vertex is (2, -2) and the axis of symmetry is x = 2.
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