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Katena32 [7]
3 years ago
7

What the vertex and AOS if the equation is y=(x-2)^2-2

Mathematics
1 answer:
Ugo [173]3 years ago
6 0

Answer:

See below.

Step-by-step explanation:

For y = a(x - b)^2 + c , the vertex is at (b, c) and the axis of symmetry is x = b.

So for y = (x-2)^2 - 2,

the vertex  is (2, -2) and the axis of symmetry is x = 2.

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Please answerrrr Graph g(x), where f(x) = 4x − 2 and g(x) = f(x + 1). a line labeled g of x that passes through points 0, negati
Mrrafil [7]

Answer:

a line labeled g of x that passes through points negative 1, negative 2 and 0, 2

Step-by-step explanation:

we have

f(x)=4x-2

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To determine g(x), substitute the variable x by (x+1) in the function f(x)

so

f(x+1)=4(x+1)-2

f(x+1)=4x+4-2

f(x+1)=4x+2

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a line labeled g of x that passes through points negative 1, negative 2 and 0, 2

4 0
3 years ago
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Lim x-1 x2 - 1/ sin(x-2)
balu736 [363]

Answer:

           \lim_{x \to 1}\frac{x^2-1}{sin(x-2)}=0

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Assuming the correct expression is to find the following limit:

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Use the property the limit of the quotient is the quotient of the limits:

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