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3 years ago

What the vertex and AOS if the equation is y=(x-2)^2-2

1 answer:

Ugo [173]3 years ago

6 0

Answer:

See below.

Step-by-step explanation:

For y = a(x - b)^2 + c , the vertex is at (b, c) and the axis of symmetry is x = b.

So for y = (x-2)^2 - 2,

the vertex is (2, -2) and the axis of symmetry is x = 2.

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