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Katena32 [7]
3 years ago
7

What the vertex and AOS if the equation is y=(x-2)^2-2

Mathematics
1 answer:
Ugo [173]3 years ago
6 0

Answer:

See below.

Step-by-step explanation:

For y = a(x - b)^2 + c , the vertex is at (b, c) and the axis of symmetry is x = b.

So for y = (x-2)^2 - 2,

the vertex  is (2, -2) and the axis of symmetry is x = 2.

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24.8 = t + 5.1 what is t?
monitta

Answer:

t = 19.7

Step-by-step explanation:

24.8 = t + 5.1

-5.1           -5.1

----------------------

19.7 = t

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2 years ago
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If c varies directly as (r + 1) and c = 8, when r= 3, calculate the value of r when c= 20.
Aneli [31]

Answer:

r = 9

Step-by-step explanation:

Given that c varies directly as (r + 1) then the equation relating them is

c = k(r + 1) ← k is the constant of variation

To find k use the condition c = 8 when r = 3, then

8 = k(3 + 1) = 4k ( divide both sides by 4 )

2 = k

c = 2(r + 1) ← equation of variation

When c = 20, then

20 = 2(r + 1) ← divide both sides by 2

10 = r + 1 ( subtract 1 from both sides )

9 = r

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{8} ⊆ {7,8,9} true or false
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the answer is false

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Meteorologists recorded a temperature change from 72˚F to 28˚F in one day. Write an equation that represents how many degrees th
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3 years ago
Consider the probabilities of people taking pregnancy tests. Assume that the true probability of pregnancy for all people who ta
Valentin [98]

Using conditional probability, it is found that there is a 0.8462 = 84.62% probability that a woman who gets a positive test result is truly pregnant.

<h3>What is Conditional Probability?</h3>

Conditional probability is the probability of one event happening, considering a previous event. The formula is:

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

  • P(B|A) is the probability of event B happening, given that A happened.
  • P(A \cap B) is the probability of both A and B happening.
  • P(A) is the probability of A happening.

In this problem, the events are:

  • Event A: Positive test result.
  • Event B: Pregnant.

The probability of a positive test result is composed by:

  • 99% of 10%(truly pregnant).
  • 2% of 90%(not pregnant).

Hence:

P(A) = 0.99(0.1) + 0.02(0.9) = 0.117

The probability of both a positive test result and pregnancy is:

P(A \cap B) = 0.99(0.1)

Hence, the conditional probability is:

P(B|A) = \frac{0.99(0.1)}{0.117} = 0.8462

0.8462 = 84.62% probability that a woman who gets a positive test result is truly pregnant.

You can learn more about conditional probability at brainly.com/question/14398287

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