Answer:
public class SwitchCase {
public static void main(String[] args) {
int num = 0;
int a = 10, b = 20, c = 20, d = 30, x = 40;
switch (num){
case 102: a += 1;
case 103: a += 1;
case 104: a += 1;
case 105: a += 1;
break;
case 208: b += 1; x = 8;
break;
case 209: c = c * 3;
case 210: c = c * 3;
break;
default: d += 1004;
}
}
}
Explanation:
- Given above is the equivalent code using Switch case in Java
- The switch case test multiple levels of conditions and can easily replace the uses of several if....elseif.....else statements.
- When using a switch, each condition is treated as a separate case followed by a full colon and the the statement to execute if the case is true.
- The default statement handles the final else when all the other coditions are false
Answer:
0010
Explanation:
Serially left shifted means that the left most bit will enter the register first. The left most bit already stored in the register will move out of the sequence. The "bold" bits mentioned below highlight these left most bits:
Initial State of the Register:
0000
Group of bits entering:
1011
<u>First Clock Cycle:</u>
0000 <em>(This bold bit will move out)</em>
1011 <em>(This bold bit will move in from right side, shifting the whole sequence one place to the left).</em>
The resulting Sequence:
0001
<u>Second Clock Cycle:</u>
0001 <em>(This bold bit will move out)</em>
1011 <em>(This bold bit will move in from right side, shifting the whole sequence one place to the left).</em>
The resulting Sequence:
0010 <em>(Final Answer)</em>
Answer:
muestra números que comienzan en 0
Explanation:
You would have to add them up need more info on the returned video
