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2 years ago

Is the point (16,20) on line ℓ?

Mathematics

1 answer:

kicyunya [14]2 years ago

7 0

Answer:

YES

Step-by-step explanation:

Find the equation of the line written as, y = kx. The graph shows a proportional relationship between y and x.

Constant of proportionality/unit rate/slope (k) = rise/run = ⁵/4.

Substitute ⁵/4 in y = kx

We would have:

y = ⁵/4x.

Using the equation of the line, we can know if a given point is on the line by plugging the value of x and y coordinates of the point into the equation. If it makes the equation true, then it is a point on the line. If it doesn't make the equation true, then it isn't a point on the line.

Let's plug in (16, 20) into y = ⁵/4x.

Thus substitute x = 16 and y = 20, we have:

[tex] 20 = \frac{5}{4}(16) [/trex]

[tex] 20 = (5)(4) [/trex]

[tex] 20 = 20 [/trex]

It makes the equation true. Therefore, the point, (16, 20) is a point on line l.

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If f(x) is the total cost, in dollars, of x cupcakes, which of the following statements best describes the meaning of f(5) = 12?

dezoksy [38]

Answer:

See below

Step-by-step explanation:

This a form of the proportional relationship:

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2 years ago

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3 years ago

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Lady bird [3.3K]

Answer:

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Step-by-step explanation:

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3 years ago

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frozen [14]

Answer:

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Step-by-step explanation:

What you need to simplify this is the following "definitions" of i to different powers.

$i^1=i$

$i^2=-1$

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3 years ago

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3 years ago

Is the point (16,20) on line ℓ?​

Is the point (16,20) on line ℓ?