Is the point (16,20) on line ℓ?

Mathematics

1 answer:

kicyunya [14]2 years ago

7 0

Answer:

YES

Step-by-step explanation:

Find the equation of the line written as, y = kx. The graph shows a proportional relationship between y and x.

Constant of proportionality/unit rate/slope (k) = rise/run = ⁵/4.

Substitute ⁵/4 in y = kx

We would have:

y = ⁵/4x.

Using the equation of the line, we can know if a given point is on the line by plugging the value of x and y coordinates of the point into the equation. If it makes the equation true, then it is a point on the line. If it doesn't make the equation true, then it isn't a point on the line.

Let's plug in (16, 20) into y = ⁵/4x.

Thus substitute x = 16 and y = 20, we have:

[tex] 20 = \frac{5}{4}(16) [/trex]

[tex] 20 = (5)(4) [/trex]

[tex] 20 = 20 [/trex]

It makes the equation true. Therefore, the point, (16, 20) is a point on line l.

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A worn, poorly set-up machine is observed to produce components whose length X follows a normal distribution with mean 14 centim

Akimi4 [234]

Answer:

74.86% probability that a component is at least 12 centimeters long.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 14$