A cylindrical container closed of both end has a radius of 7cm and height of 6cm A.)find the total surface area of the container

Question

3 years ago

10

B.) find the volume of the container

1 answer:

emmasim [6.3K] · Answer 1 · 2022-08-01T14:05:05+03:00

Answer:

Step-by-step explanation:

Surface:

surface area = 2 ends + side

The ends are both a circle and they are identical.

area of a circle = $\pi$ $r^{2}$

then $\pi$ $7^{2}$ = 153.93804 $cm^{2}$

since there are two ends multiply the above by 2

2*153.93804 =307.87608 $cm^{2}$

the side is the length * height

length = perimeter of the circle , the perimeter of a circle is also the circumference. circ = 2 $\pi$ r

circ = 2* $\pi$ *7 = 53.407075

surface area of the side = 6* 53.407075=320.44245

add the two surfaces areas together :)

total surface area = 320.44245 + 307.87608 = 628.3185307 $cm^{2}$

Volume:

volume is the area of the end times the height

volume = circle area * height

volume = 153.93804 * 6

volume = 923.62824 $cm^{3}$