Question

A cylindrical container closed of both end has a radius of 7cm and height of 6cm A.)find the total surface area of the container B.) find the volume of the container

Answer 1

Answer:

Step-by-step explanation:

Surface:

surface area = 2 ends + side

The ends are both a circle and they are identical.

area of a circle = $\pi$$r^{2}$

then  $\pi$$7^{2}$ = 153.93804 $cm^{2}$

since there are two ends multiply the above by 2

2*153.93804 =307.87608 $cm^{2}$

the side is the length * height

length = perimeter of the circle , the perimeter of a circle is also the circumference.   circ = 2$\pi$r

circ = 2*$\pi$*7 = 53.407075

surface area of the side = 6* 53.407075=320.44245

add the two surfaces areas together :)

total surface area = 320.44245 + 307.87608 = 628.3185307 $cm^{2}$

Volume:

volume is the area of the end times the height

volume = circle area * height

volume = 153.93804 * 6

volume = 923.62824 $cm^{3}$