Answer: B (0.17, 2.33)
Step-by-step explanation:
A P E X
Answer:
To prove that 3·4ⁿ + 51 is divisible by 3 and 9, we have;
3·4ⁿ is divisible by 3 and 51 is divisible by 3
Where we have;
= 3·4ⁿ + 51
= 3·4ⁿ⁺¹ + 51
-
= 3·4ⁿ⁺¹ + 51 - (3·4ⁿ + 51) = 3·4ⁿ⁺¹ - 3·4ⁿ
-
= 3( 4ⁿ⁺¹ - 4ⁿ) = 3×4ⁿ×(4 - 1) = 9×4ⁿ
∴
-
is divisible by 9
Given that we have for S₀ = 3×4⁰ + 51 = 63 = 9×7
∴ S₀ is divisible by 9
Since
-
is divisible by 9, we have;
-
=
-
is divisible by 9
Therefore
is divisible by 9 and
is divisible by 9 for all positive integers n
Step-by-step explanation:
I think that the answer is 3x/2yz^3 because I did [(27x^2y^4/16yz^4)*(8z/9xy^4)].
A and B Definitely. 3 and 17, -3 and -17